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sammy [17]
3 years ago
14

general admission tickets to the fair cost $3.50 per person ride passes cost an additional $5.50 per person parking called 6 for

the family the total cost for the ride passes and parking was $51 how many people in the family attended the fair
Mathematics
1 answer:
pantera1 [17]3 years ago
8 0
To solve this, you must define the variable first.
You can usually choose the variable to be what we are asked to find.

Let the number of people in the family be x.

The amount paid by each person (x) for admission and ride passes was $3.50+$5.50=$9.00

Only one payment for parking ($6) was made by the family.

The total amount spent was $9×x+$6
The total amount spent was $51.

Therefore, 5 people in the family went to the fair.
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The measure of the side QR is 8.8.

Step-by-step explanation:

Since LMNO \sim PQRS, then SP \propto OL, RS \propto ON, RQ \propto MN and QP \propto LM. From figure we have the following relationship:

k = \frac{OL}{SP} = \frac{ON}{RS} = \frac{MN}{QR} = \frac{ML}{QP} (1)

Where k is the proportionality ratio.

If we know that SP = 13, OL = 55, MN = 37, then the measure of side QR is:

k = \frac{OL}{SP} (1b)

k = \frac{55}{13}

k = \frac{MN}{QR}

QR = \frac{MN}{k} (1c)

QR = \frac{37}{\frac{55}{13} }

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The measure of the side QR is 8.8.

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Whose graph is shown in the second figure below. So we can get the graph of f from the graph of g this way:

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