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m_a_m_a [10]
4 years ago
14

Find x when y=-2 if x=16 when y=8

Mathematics
1 answer:
babunello [35]4 years ago
4 0
Well make them a fraction : -2/16 = 8/x. Find the value of x.
<span><span><span>
−2/</span>16</span>=<span>8/x</span></span>
<span><span>−<span>2*x</span></span>=<span><span>(8)</span>*<span>(16)</span></span></span><span><span>
−<span>2x</span></span>=128</span>
<span><span><span>−<span>2x/</span></span><span>−2</span></span>=<span>128/<span>−2</span></span></span><span>
x=<span>−<span>64

</span></span></span>-2/16 = 8/-64 (True)

Hoped I helped!
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2 years ago
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a_sh-v [17]

Answer:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And repaplacing we got:

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\bar X_C = 28.714 the sample mean for treatment

s_T= 4.461 the sample deviation for treatment

s_C= 7.387 the sample deviation for control

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The degrees of freedom are given by:

df= 7+7-2= 12

The confidence interval for the difference of means is given by:

(\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}

The confidence is 98% so then the significance is \alpha=0.02 and \alpha/2 =0.01. Then the critical value would be:

t_{\alpha/2}=2.681

And replacing we got:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

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Answer:

Pls make the question a bit more clear

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