What are the factors of 49?
2 answers:
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Answer:
3y²z³ / 2x
Step-by-step explanation:
we can take one term at a time:
9/6 can be simplified to 3/2
x²÷x³ = x^-1 which equals
y³÷y = y²
z⁵÷z² = z³
put it all together:
3··y²·z³ / 2 or
3y²z³ / 2x
Get everything on one side: 
. Now we can factor to find the solutions. What we ask ourselves here is "What 2 numbers will add to be +4 and multiply to be -21?" +7 and -3 work because 7-3 = 4 and 7 * -3 = -21. So our factors are (x+7)(x-3). Our solutions, however, are found using the Zero Product Property. If x + 7 = 0, then x = -7. If x - 3 = 0, then x = 3. So our solutions are x = -7 and x = 3.