1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Jlenok [28]
3 years ago
10

Find the perimeter of this triangle.HELP ASAP!!!!​

Mathematics
1 answer:
irga5000 [103]3 years ago
4 0

Answer: 119

Step-by-step explanation: base * height / 2

14*17/2=119. can i get Brainliest please

You might be interested in
Just help please, im the NOT smartest
olasank [31]

Answer: 3/7

The slope is the same.

4 0
2 years ago
Read 2 more answers
Find the value of x and y.
Leya [2.2K]

Answer:

x = 63 y = 27

Step-by-step explanation:

The straight line is 180 degrees

subtract 117 from 180 to get 63

It says x+7= 90, so subtract x(63) from 90 to get 27

4 0
3 years ago
What 2 numbers multiply to -18 and add up to -4
ivann1987 [24]

Answer:

-9 x 1 x 1 x 1 x 2 = (-18)

-9 + 1 + 1 + 1 + 2 = (-4)

5 0
3 years ago
Suppose each runner ran at the rate given in the table above for 3.1 miles. How much time will elapse between the first place fi
Scilla [17]
You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:

Runner         distance           time

Arabella        7,299 feet        561 seconds
Bettina          3,425 yards     13 minutes, 12 seconds
Chandra       8,214 feet        0,195 hours
Divya            1,62 miles        732 seconds

To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.

First you need to convert the data to obtain the rate in miles per second.

These are the main conversion identities:

1 mile = 5280 feet

1 mile = 1760 yards

1 hour = 3600 seconds

1 hour = 60 minutes

1 minute = 60 seconds

Arabella:

rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet)  =

= 0.00244 mile/second

Time to run 3.1 miles: V = d / t => t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds

Bettina:

13 minutes + 12 seconds = 13*60 seconds +12 seconds = 792 seconds

rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds

Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds

Chandra:

rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =

= 0.00222 seconds

Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds

Divya:

rate = 1.62 miles / 732 seconds = 0.00221 seconds

Time = 3.1 mile / 0.00221 seconds = 1403 seconds

Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds

That is equivalent to 2.38 seconds.
6 0
3 years ago
Mary is preparing for her college entrance exams in a practice test she answered 12 problems in 30 minutes at this rate how many
kap26 [50]

Answer:

40 problems in 100 minutes

Step-by-step explanation:

This is a ratio problem.

You first divide 30 minutes by three to get how many problems she can do in 10 minutes. What you do to one side you do to the other side. So then, you should have 4 problems in 10 minute. Then, you multiply 10 by 10 and 4 by 10 to get 40 problems in 100 minutes.

6 0
3 years ago
Other questions:
  • Suppose that all sides of a quadrilateral are equal in legth and opposite sides are parallel. Use vector methods to show that th
    9·1 answer
  • What is the answer to (7*x+9)*x+90
    11·1 answer
  • in a class, 60% of the students are girls. there are 19 girls in the class. how many students are there? how many boys are there
    9·1 answer
  • How do i graph this NEED ASAP​
    12·1 answer
  • What is 5.8×10^6 seconds in minutes?
    10·2 answers
  • B) fully factorise <br>7x - 49​
    9·1 answer
  • Find the value of y.
    15·1 answer
  • 10x+17+5y+3 what is the answer to my question
    5·2 answers
  • Could someone answer this pls??
    7·2 answers
  • Help me out please :(
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!