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Leto [7]
3 years ago
8

10% of Kindergarteners know how to read before school starts. If there are 150 kindergarteners at a

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
7 0
10% = 0.10

0.10 x 150 = 15

So 15 kids are able to read on the first day of school!
Tamiku [17]3 years ago
3 0

Answer:

15

Step-by-step explanation:

To get 10 percent, you divide by 10.

150 divided by 10 equals 15.

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A farmer in Gervais is raising zebras and elephant. Last week, she bought 15 bags of feed. Zebra feed costs $35 a bag and elepha
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3 times a certain number n is added to 6, the sum is 20 more than the original
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3 years ago
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
Determine the domain and the range of the​ relation, and tell whether the relation is a function.
weeeeeb [17]
Domain is: {10,26,40,56} and it is not a function
3 0
2 years ago
Read 2 more answers
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