Question

Find the area of the given figure which have all the squares corners.​

Answer 1

Answer:

The area of the given figure is 58 m².

Step-by-step explanation:

Dividing the given figure into two parts :

• ➛ Big rectangle
• ➛ Small rectangle

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Firstly, finding the area of bigger rectangle by substituting the values in the formula :

$\longrightarrow{\pmb{\sf{A_{(Rectangle)} = l \times b}}}$

• ➣ l = 12 m
• ➣ b = 4 m

$\begin{gathered} \qquad\longrightarrow{\sf{A_{(Rectangle)} = l \times b}}\\\\\qquad{\longrightarrow{\sf{A_{(Rectangle)} = 12\times 4}}}\\\\\qquad{\longrightarrow{\sf{A_{(Rectangle)} =48}}}\\\\\qquad{\star{\underline{\boxed{\sf{\pink{A_{(Rectangle)} =48 \: {m}^{2}}}}}}} \end{gathered}$

Hence, the area of bigger rectangle is 48 m².

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Secondly, finding the area of smaller rectangle by substituting the values in formula :

$\longrightarrow{\pmb{\sf{A_{(Rectangle)} = l \times b}}}$

• ➠ l = 5 m
• ➠ b = 2 m

$\begin{gathered} \qquad\longrightarrow{\sf{A_{(Rectangle)} = l \times b}}\\\\\qquad{\longrightarrow{\sf{A_{(Rectangle)} = 5\times 2}}}\\\\\qquad{\longrightarrow{\sf{A_{(Rectangle)} =10}}}\\\\\qquad{\star{\underline{\boxed{\sf{\purple{A_{(Rectangle)} =10 \: {m}^{2}}}}}}} \end{gathered}$

Hence, the area of smaller rectangle is 10 m².

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Now, finding the total area of given figure by substituting the values in the formula :

$\longrightarrow{\pmb{\sf{Total \: Area = A_{(Big)} + A_{(Small)}}}}$

• → $\rm{A_{(Big)}}$ = Area of big rectangle
• → $\rm{A_{(Small)}}$ = Area of small rectangle

$\begin{gathered} \qquad{\longrightarrow{\sf{Total \: Area = A_{(Big)} + A_{(Small)}}}} \\ \\ \quad{\longrightarrow{\sf{Total \: Area = 48 + 10}}} \\ \\ \quad{\longrightarrow{\sf{Total \: Area = 58}}} \\ \\ \quad{\star{\underline{\boxed{\sf{\red{Total \: Area =58\: {m}^{2}}}}}}} \end{gathered}$

Hence, the total area of the given figure is 58 m².

$\rule{300}{2.5}$

Answer 2

Answer:

area of the given figure: 58 m²

Explanation:

area of rectangle: length * width

total area:

( 2 * 5 + 12 * 4 )

58 m²