Answer:
false
Step-by-step explanation:
Answer:
Step-by-step explanation:
xy = 300
x + y = 50 Solve for y
y = 50 - x substitute into xy = 300
x(50 - x) = 300 Remove the brackets.
50x - x^2 = 300 Bring the left to the right.
0 = x^2 - 50x + 300
This is a quadratic. It will have 2 solutions.
a=1
b = - 50
c = 300
Put these into the quadratic equation.
It turns out that x has two values -- both plus
x1 = 42.03
x2 = 6.97
x1 + y1 = 50
42.03 + y = 50
y = 50 - 42.03
y = 7,97
(42.03 , 7.97)
====================
x2 + y2 = 50
6.97 + y2 = 50
y2 = 50 - 6.97
y2 = 43.03
(6.97 , 43.03)
Answer:
Answer is 2×c + log [10^{a} + 10^{b}] +a
Step-by-step explanation:
log 2 = a ,log 3 = b , log 7 = c
Using formula
<em>log d×e = log d + log e</em>
<em> log d^{a} = a×log d</em>
<em> log 5 = log [10^{a} + 10^{b}]</em>
log 490 in terms of a , b and c and you can have integer coefficients
log 490
= log 7^{2}×5×2
= 2×log 7 + log 5 + log 2
= 2×c + log [10^{a} + 10^{b}] +a
Answer is 2×c + log [10^{a} + 10^{b}] +a
Simply 4/6 to its equivalent fraction of 2/3
Is 1/3 of a cup enough for the 2/3 a cup needed? No. So he doesn't have enough
angles in a triangle need to equal 180 degrees
so x = 180 - 47 - 58
x = 180-105
x= 75 degrees
