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Katena32 [7]
3 years ago
14

zoey inflates 24 balloons for decorations at the middle school dance. if zoey inflated 15% of the total number of balloons for t

he dance, how many balloons are there total?
Mathematics
2 answers:
kirill [66]3 years ago
5 0

Answer:

160

Step-by-step explanation:

Divide 24 by 15 percent (.15)

24/.15

=160

Vlad1618 [11]3 years ago
4 0

Answer:

160

Step-by-step explanation:

from the question, we know that 24 balloons are 15% of total.

make equation:

\frac{15}{100} =\frac{24}{x}

calculate:

100*24/15=160 balloons

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3 years ago
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According to the Central Limit Theorem, which statements(s) are TRUE. There may be more than 1 correct answer. A. An increase in
Liono4ka [1.6K]

Answer:

Options A, B and C are correct.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

From the Central Limit Theorem, we have that:

The larger the sample size, the closer to the normal distribution the distribution of sample means is.

No matter the sample size, the mean is the same.

The larger the sample size, the smaller the standard deviation.

The smaller the sample size, the larger the standard deviation.

So the correct options are:

A, B, C

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2 years ago
Help pls this has been bugging me for so long and I need the quickest answers please I need answers done by 12:24 nothing to rus
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Help<br>evaluate 12-3×2+1​
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Step-by-step explanation:

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Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!
Trava [24]
\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span>\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.
\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.
--------------------
5y = 12
\boxed{\boxed{y =  \frac{12}{5}}}\end{array}}\qquad\quad\checkmark

Let's replace the value found in the first equation:
4x-3y=16\:(I)
4x-3*( \frac{12}{5}) =16
4x -  \frac{36}{5} = 16
least common multiple (5)
\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}
20x - 36 = 80
20x = 80 + 36
20x = 116
x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark



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3 years ago
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