Answer:
72 km
Step-by-step explanation:
We can use basic logic to find how many miles you run in 12 weeks.
If you run for 2 km 3 times a week, then you run 6 km per week because 
.
If you continue this for 12 weeks, that means you will have ran 
km, which can simplify down to 72 km.
Hope this helped!
You actually have to do the break our rooms to find the code wish i could help
Here u gooo hope this helps
A) We are told that at 2 hours, the velocity is 18 km/h and at 4 hours, the velocity is 4 km/h. Since we are relating two variables - let's give them names.
Let x = time and y = velocity. Since the velocity depends on the time (that is, the time influences velocity), this is a linear function. Any linear function can be written in slope intercept form as y = mx + b. The problem wants the situation in standard from of Ax + By = C, which can be found from slope intercept form.
So now we can make our line. Consider the ordered pairs of (2,18) and (4, 4) with them in (x, y) form. Finding the slope, m, between these points is as such:
m = y₂-y₁ / x₂-x₁
m = 4 - 18 / 4 - 2
m = -14 / 2 = -7.
Our slope is -7.
We take m = -7, x = 4, and y = 4 (it goes 4 km/h in 4 hrs) and use those three things to find the y-intercept.
y = mx + b
4 = -7 * 4 + b
4 = -28 + b
32 = b
So our equation of the line is y = -7x + 32. To put the equation into standard form, we need to place all the variables on one side of the equals sign, all the numbers on the other.
y = -7x + 32
7x + y = 32
In standard form, the equation for this situation is 7x + y = 32
***
To find out the velocity at 8 hours, we evaluate our function at x = 8. Either equation (standard form or slope intercept) works; we use standard form.
7x + y = 32
7*8 + y = 32
56 + y = 32
y = -24
At a time of eight hours, the bicycle is moving at -24 km/h.
Answer:
x=-1, x=3 e x=2i, x=-2i
Step-by-step explanation:
Solve for x over the real numbers:
x^4 - 2 x^3 + x^2 - 8 x - 12 = 0
The left hand side factors into a product with three terms:
(x - 3) (x + 1) (x^2 + 4) = 0
Split into three equations:
x - 3 = 0 or x + 1 = 0 or x^2 + 4 = 0
Add 3 to both sides:
x = 3 or x + 1 = 0 or x^2 + 4 = 0
Subtract 1 from both sides:
x = 3 or x = -1 or x^2 + 4 = 0
Subtract 4 from both sides:
x = 3 or x = -1 or x^2 = -4
x^2 = -4 has no solution since for all x on the real line, x^2 >=0 and -4<0:
Answer: |
| x = 3 or x = -1
