2 years ago

Question 7

Mathematics

1 answer:

SpyIntel [72]2 years ago

6 0

Answer:

Eric = 22

Teresa = 12

Abdul = 66

Step-by-step explanation:

Eric = 10 + Teresa

Abdul = 3*Eric

Teresa = Eric - 10

3E +E + (E-10 ) =100

5E = 110

E=22

You might be interested in

X = ?<br><br>Find the composite function 20 points and brainliest

masha68 [24]

Answer:

Explanation:

fg(x) = (x+2)(3x^2 - 1)
= 3x^3 - x + 6x^2 - 2
= 3x^3 + 6x^2 - x - 2

gf(x) = (3x^2 - 1)(x + 2)
= 3x^3 + 6x^2 - x - 2

As you can see:

fg(x) = gf(x)
3x^3 + 6x^2 - x - 2 = 3x^3 + 6x^2 - x - 2

5 0

2 years ago

A building is 139 ft tall.at noon it cast a shadow a 219- ft.what is the sun’s angle of elevation at that time.

adelina 88 [10]

Answer:

S = 32.4 degrees

7 0

2 years ago

Solve the equation A = bh for b. b = Ah b = A/h b = h/A b = h – A Solve the equation A = bh for b. b = Ah b = A/h b = h/A b = h

Leto [7]

Answer:

The answer is " $b=\frac{A}{h}$ ".

Step-by-step explanation:

Therefore in this question the "bh" were the multiplied and these values includes the variable which is solving by the isolating of "b".

Let's Divides the both sides for h.

$\to \frac{A}{h} = \frac{bh}{h}\\\\\to \frac{A}{h} = b\\\\\to b= \frac{A}{h}$

7 0

2 years ago

If your cell phone bill was $67.85 and there is a 7.5% late fee how much will your bill be?

dedylja [7]

$67.85 \times .075 = 5.08875 \\ 67.85 + 5.08875 = 72.94$
bill is $72.94

6 0

3 years ago

Read 2 more answers

Power (denoted by PPP) can be defined as a function of work (denoted by WWW) and time (denoted by ttt) using this formula: P=\df

Amanda [17]

Answer:

$\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$

Step-by-step explanation:

Power (denoted by P) can be defined as a function of work (denoted by W) and time (denoted by t) using this formula:

$P=\dfrac{W}{t}$

Unit of Work = $\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2}$

Unit for Time = s

Therefore, the Unit of Power

$=$Unit for W \times \dfrac{1}{\text{Unit for time}}$

$=\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2} \times \dfrac{1}{s} \\=\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$

An appropriate unit for power is: $\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$

3 0

2 years ago