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PilotLPTM [1.2K]
2 years ago
10

Question 7

Mathematics
1 answer:
SpyIntel [72]2 years ago
6 0

Answer:

Eric = 22

Teresa = 12

Abdul = 66

Step-by-step explanation:

Eric = 10 + Teresa

Abdul = 3*Eric

Teresa = Eric - 10

3E +E + (E-10 ) =100

5E = 110

E=22

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 3 4 is the answer  tos thi
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Divide 3xsquared - 11x - 4 by x - 4<br><br>a. x+1<br>b. x-23<br>c. 3x+1<br>d. 3x-23​
Dmitriy789 [7]

Answer:

c. 3x+1

Step-by-step explanation:

Since the divisor is in the form of x - c, use what is called Synthetic Division. Remember, in this formula, <em>-c</em> gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 3 −11 −4

↓ 12 4

_______________

3 1 0 → 3x + 1

You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [3x² - 11x - 4]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 3 in your quotient can be a 3x, and the 1 follows right behind it, giving you the quotient of 3x + 1.

I am joyous to assist you anytime.

5 0
3 years ago
Write the ratio as a fraction in simplest form.<br><br>56 days to 5 weeks​
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Step-by-step explanation:

8 0
3 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

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$p_2=\frac{86}{155}=0.554839

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The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

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Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

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I would be happy to help with this question!
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