27.3= 3/4y what does y equal?

Please help this is for rotc it's due at 6

Gnom [1K]

Answer:

UK, Egypt, India, the Philippines, Colombia,

Step-by-step explanation:

5 0

3 years ago

Find the area of the figure:

astra-53 [7]

Answer:

To find the area of she shaded part we first need to find the total of the area.

L x W

8 x 5 = 40 is the total area

Now we need to find the area of the non - shaded part

Since it is a square all sides are equal the short lines sticking from the sides indicate that

2 x 2 = 4

Now we subtract the total area from the non shaded area.

40 - 4 = 36

4 0

2 years ago

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A point has been translated left and down. Based on the graph, which could be true? Check all that apply.

notka56 [123]

B is the image of D, B is the image of E and C is the image of D

These are the only points where the image is to the left and down from the stated point.

6 0

3 years ago

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What is the equation of the line that passes through the points (4/5,1/5) and (1/2,3/2)?

Setler [38]

Answer:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$ point-slope form

$13x+3y=11$ (standard form)

Let me know if you prefer another form.

Step-by-step explanation:

The slope of a line can be found using $\frac{y_2-y_1}{x_2-x_1}$ provided you are given two points on the line.

We are.

Now you can use that formula. But I really love to just line up the points vertically then subtract them vertically then put 2nd difference over 1st difference.

(4/5 , 1/5)

-( 1/2 , 3/2)

-----------------

3/10 -13/10

2nd/1st = $\frac{\frac{-13}{10}}{\frac{3}{10}}=\frac{-13}{3}$ is our slope.

So the following is point-slope form for a linear equaiton:

$y-y_1=m(x-x_1) \text{ where } m \text{ is slope and } (x_1,y_1) \text{ is a point on the line }$

Plug in a point $(x_1,y_1)=(\frac{1}{2},\frac{3}{2}) \text{ and } m=\frac{-13}{3}$ .

This gives:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$

I'm going to distribute:

$y-\frac{3}{2}=\frac{-13}{3}x-\frac{-13}{6}$

Now I don't like these fractions so I'm going to multiply both sides by the least common multiply of 2,3, and 6 which is 6:

$6y-9=-26x+13$

Add 26x on both sides:

$26x+6y-9=13$

Add 9 on both sides:

$26x+6y=22$ This is actually standard form of a line.

It can be simplified though.

Divide both sides by 2:

$13x+3y=11$ (standard form)

7 0

3 years ago

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Algebra 1 question 4.

Brrunno [24]

Greetings!

To start this problem, let's first assign a variable for the missing, consecutive odd numbers. Since they are consecutive and odd, we add two.

Proof: 3-1=2, 5-3=2

The first, consecutive, odd number: $x$

The second, consecutive, odd number: $x+2$

The third, consecutive, odd number: $x+4$

The fourth, consecutive, odd number: $x+6$

The sum of the values are equal to 3 times the sum of the first two numbers, of which this is equal to 35 less than the fourth number. Let's create an equation to simplify this:

$3((x)+(x+2))=(x+6)-35$