By definition of <em>surface</em> area and the <em>area</em> formulae for squares and rectangles, the <em>surface</em> area of the <em>composite</em> figure is equal to 166 square centimeters.
<h3>What is the surface area of a composite figure formed by two right prisms?</h3>
According to the image, we have a <em>composite</em> figure formed by two <em>right</em> prisms. The <em>surface</em> area of this figure is the sum of the areas of its faces, represented by squares and rectangles:
A = 2 · (4 cm) · (5 cm) + 2 · (2 cm) · (4 cm) + (2 cm) · (5 cm) + (3 cm) · (5 cm) + (5 cm)² + 4 · (3 cm) · (5 cm)
A = 166 cm²
By definition of <em>surface</em> area and the <em>area</em> formulae for squares and rectangles, the <em>surface</em> area of the <em>composite</em> figure is equal to 166 square centimeters.
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Answer:
Step-by-step explanation:
x²-7x+10=0
(x-2)(x-5)=0
x=2 or x=5
Answer:
12
Step-by-step explanation:
(x-1)+(y+1)+(z-1)
= x -1 + y + 1 + z - 1
= x + y + z -1
= (x + y + z) -1
given that x+y+z = 13, substitute this value into the equation aove
(x + y + z) -1
= 13 - 1
= 12
Answer:
The radius is increasing at a rate of approximately 0.044 in/s when the diameter is 12 inches.
Because
the radius is changing more rapidly when the diameter is 12 inches.
Step-by-step explanation:
Let
be the radius,
the diameter, and
the volume of the spherical balloon.
We know
and we want to find 
The volume of a spherical balloon is given by

Taking the derivative with respect of time of both sides gives

We now substitute the values we know and we solve for
:



The radius is increasing at a rate of approximately 0.044 in/s when the diameter is 12 inches.
When d = 16, r = 8 and
is:

The radius is increasing at a rate of approximately 0.025 in/s when the diameter is 16 inches.
Because
the radius is changing more rapidly when the diameter is 12 inches.