Answer:
cm per second
![\frac{dS}{dt}=320 square centimeter per secondStep-by-step explanation:We are given that volume of sphere [tex]V=\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=%5Cfrac%7BdS%7D%7Bdt%7D%3D320%20square%20%20centimeter%20per%20second%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EWe%20are%20given%20that%20volume%20of%20sphere%20%3C%2Fp%3E%3Cp%3E%5Btex%5DV%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
Volume of sphere is increasing at a constant rate
cubic centimeters per second
We have to find the rate of radius at which increasing
when r= 10 cm
Differentiating w.r.t time


cm per second
Now ,we are given that surface area of sphere

Differentiate w.r.t time then we get


cm per second
Answer:
16 : 5
Step-by-step explanation:
For 2 similar polygons with ratio of sides/perimeter = a : b
Then the ratio of areas = a² : b²
Here the ratio of areas = 256 : 325
Hence ratio of perimeters = √256 : √325 = 16 : 5 √13
Answer:
x = 4
Therefore, for the triangles to be congruent by HL, the value of x must be 4.
Step-by-step explanation:
Given: ΔABC and ΔHGL are congruent. ∠ABC = ∠HGL = 90°.
Length of hypotenuse AC = 15
Length of hypotenuse HL = 3x + 3
Length of AB = 9, Length of BC = 12 and Length of GL = 2x + 1.
Sol: ∵ ΔABC ≅ ΔHGL
Length of HL = Length of AC (corresponding parts of congruent triangles)
3x + 3 = 15
3x = 15 - 3
3x = 12
x = 12/3 = 4
Therefore, for the triangles to be congruent by HL, the value of x must be 4.
For this case you can model the problem as a rectangle triangle where you have the length of the opposite leg and the adjacent leg.
Therefore, the angle sought is given by:
theta = Atan (8/15)
theta = 28.07 degrees
Answer:
The angle between its diagonal and a longer edge is:
theta = 28.07 degrees
Answer A 7.6 earthquake is more than 2x more powerful than a 3.2
Step-by-step explanation: