A. left 2 units
the vertex form of a parabola is
y = a(x-h)^2 + k
(h,k) is the point of the vertex
since h is -2 in (x+2)^2
the function is shifted 2 units left
Answer:
Range is number of copies produced and set of values is; 1 ≤ N ≤ 200
Domain; Cost of publishing book in dollars; set of values are; $710 ≤ N ≤ $2700
Step-by-step explanation:
Range is a set of all the possible output values in a function while domain is the set of all possible input values.
Now, the function is given as;
C = 10N + 700
Where;
C is the cost of publishing the book in dollars
N is the number of copies of books produced
Thus, the domain will be a set of N values while Range will be a set of C values.
We are told that the first printing can produce up to 200 copies of the book.
That means a maximum of 200 books and a minimum of 1.
Thus;
Range is; 1 ≤ N ≤ 200
Maximum possible cost of the 200 books is;
C = 10(200) + 700
C = $2700
Minimum cost which will be for 1 book will be;
C = 10(1) + 700
C = $710
Thus,domain is;
$710 ≤ N ≤ $2700
Easy
differnce of 2 perfect squares
a²-b²=(a+b)(a-b)
in this case
x⁴=(x²)²
16=4²
(x²)²-4²=(x²+4)(x²-4)
x²-4 can be factored since 4=2²
x²-2²=(x+2)(x-2)
complete factored form is
(x²+4)(x+2)(x-2)
gegroup to seperate (x+2)
(x+2)[(x²+4)(x-2)]
(x+2)p(x)
p(x)=(x²+4)(x-2)
expanded
p(x)=x³-2x²+4x-8
Answer:
x = 6 and y = - 6
Step-by-step explanation:
- 4 x - 2 y = -12.......equ No 1
4 x + 8y = - 24.......equ No 2
Adding equ No 1 and equ No 2
6 y = - 36
∴ y = - 6
substitute y = - 6 in equ No 2
4 x + 8 y = -24
4 x + 8 ×( -6) = - 24
4 x - 48 = -24
4 x = -24 + 48
4 x = 24
∴ x = 6
x = 6 and y = - 6
