The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
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38.97 would be standard form
7(2+5v)=3v+14
14+35v=3v+14
-3v -3v
14+32v=14
-14 -14
32v=0
÷32 ÷32
v=0
hope this helps!!
When it hits the ground the height would be 0.
Set h to 0 and solve for t ( time)
0 = -16t^2 + 112t + 144 divide both sides by -16:
T^2 -7t -9
Factor the polynomial :
( t- 8.1) (t+1.1
Solve for t setting each equation to 0:
T = 8.1 or t = -1.1
Time has to be positive, so the answer is
8.1 seconds
Depending on how everything gets rounded it could also be 8 seconds.
Answer:
25
Step-by-step explanation:
