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RoseWind [281]
3 years ago
13

One letter tile is drawn from the bag and replaced 300 predict how many

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0
Forgive me if i'm wrong but does't the question answer itself almost like a trick because the question is one letter title is drawn so is there one one letter tile if there only one letter tile then the answer 300 hope i helped :3
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A box is filled with 10 brown cards , 4 yellow cards, and 4 red cards. A card is chosen at random from the box. What is the prob
Setler [38]
The answer is 2/9

explanation:
10+4+4= 18 cards in the box
and there are 4 red cards in the box, so it’s 4/18. u divide both sides by 2, which gives u the simplest version, 2/9.
5 0
3 years ago
Which ordered pair is NOT a solution of y = 2x +1?
Phantasy [73]

Answer:

C. y=2x+1

2×3=6

6+1=7

2×0=0

0+1=1

2×-1=-2

-2+1=-1

therefore answer=C

3 0
2 years ago
Solve for x thanks .
OleMash [197]

Answer:

x = 3.87

Step-by-step explanation:

Using the right angle altitude theorem, we know that all three triangles are congruent, so the lengths of corresponding sides of the triangles are in proportion..

AD/DB = DB/DC

15/x = x/1

x² = 15

x = √15

x = 3.87

8 0
2 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
Please help!! Will give brainliest
Angelina_Jolie [31]

Answer:

b) 16 rt 2

Step-by-step explanation:

using the 45-45-90 triangle trick,

let x=16

then BC is x rt 2, or 16 rt 2

4 0
3 years ago
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