Answer:
Distance from the airport = 894.43 km
Step-by-step explanation:
Displacement and Velocity
The velocity of an object assumed as constant in time can be computed as
Where 
is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as
The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as
The displacement of the plane in 2 hours is
Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are
The displacement in 1 hour is
The total displacement is the vector sum of both
The distance from the airport is the module of the displacement:
Answer:
1872
Step-by-step explanation:on edge
For question 22, divide each number by 1.41 to see which one produces a quotient larger than 0.9. d is the answer.
For #23, multiple 0.155 million by 86%, the result is 133,300
again, d is the correct answer.
First we have to find the mean (average)
mean = (564 + 1000 + 848 + 1495 + 1348) / 5 = 5255 / 5 = 1051
now we subtract the mean from every data point, then square it
564 - 1051 = -487......-487^2 = 237169
1000 - 1051 = -51......-51^2 = 2601
848 - 1051 = -203......-203^2 = 41209
1495 - 1051 = 444......444^2 = 197136
1348 - 1051 = 297......297^2 = 88209
now find the mean of the results.....but know when ur dealing with a sample instead of the whole population, u divide by 1 number less...so instead of dividing by 5, u divide by 4.
(237169 + 2601 + 41209 + 197136 + 88209) / 4 = 566324 / 4 =
141581.....this is called ur variance
now take the square root of the variance and u have ur standard deviation
sqrt (141581) = 376.272 rounds to 376.27 <==
