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2 years ago

6

Create a system of linear equations with no solution. In your final answer, include the system of equations and the graphs of th

e lines.

2 answers:

irakobra [83]2 years ago

8 0

Nice name and uhhhhhh don’t know what to tell you I failed math in middle school and high school so good luck

Georgia [21]2 years ago

3 0

Answer:

sdgggggggggggggggggggggggggggg

Step-by-step explanation:

You might be interested in

Lisa divided the irregular polygon into 2 rectangles with a line.

Bogdan [553]

Here's the link for the image: http://assets.openstudy.com/updates/attachments/5507589de4b01982d6668698-winsteria-1426544809579-ms_......

The correct is this one: "d. 3(9) + 7(5)." Lisa divided the irregular polygon into 2 rectangles with a line. The <span> expression that can be used to find the area of the irregular polygon is 3(9) + 7(5). That will give you the total are of the two rectangles.</span>

3 0

3 years ago

Find the absolute maximum and absolute minimum values of f on the given interval.

anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

$f(x)=xe^{-\frac{x^{2}}{32} }$ , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

$f(x)=xe^{-\frac{x^{2}}{32} }$

Using the product rule, first derivative will be:

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$ = 0

$1-\frac{x^{2}}{16}=0$

$\frac{x^{2}}{16}=1$

$x^{2}=16$

x = ±4

x can't be -4 because it is not in the interval [-2,8].

$f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76$

$f(4)=4e^{-\frac{4^{2}}{32} }=2.42$

$f(8)=8e^{-\frac{8^{2}}{32} }=1.08$

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0

3 years ago

Which of the following appear in the diagram below?? check all that apply

bulgar [2K]

Check all options:

A. The notion $\overleftrightarrow{YX}$ represents the line YX. As you can see the line YX is present in the diagram.

B. Start with point Z, go to the point X and then to the point Y. You path is along ∠ZXY sides, this means that you can see ∠ZXY on the picture.

C. The notion $\overrightarrow{ZX}$ represents the ray ZX. On the picture is given segment ZX, not ray, then this option is false.

D. To form the ∠XYZ you have to connect points Z and Y. Without this connection ∠XYZ cannot be seen. This option is false.

Answer: True options are A and B.

6 0

4 years ago

Read 2 more answers

The breaking strength of a rivet has a mean value of 10,000 psi and a standard deviation of 500 psi. (a) What is the probability

velikii [3]

Answer:

a) 89.05% probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200

b) No, because one of the requirements of the central limit theorem is a sample size of at least 30.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 10000, \sigma = 500$

(a) What is the probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200?

Here we have $n = 40, s = \frac{500}{\sqrt{40}} = 79.06$

This probability is the pvalue of Z when X = 10200 subtracted by the pvalue of Z when X = 9900. So

X = 10200

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{10200 - 10000}{79.06}$

$Z = 2.53$

$Z = 2.53$ has a pvalue of 0.9943.

X = 9900

$Z = \frac{X - \mu}{s}$

$Z = \frac{9900 - 10000}{79.06}$

$Z = -1.26$

$Z = -1.26$ has a pvalue of 0.1038.

0.9943 - 0.1038 = 0.8905

89.05% probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200

(b) If the sample size had been 15 rather than 40, could the probability requested in part (a) be calculated from the given information?

No, because one of the requirements of the central limit theorem is a sample size of at least 30.

3 0

3 years ago

Whats is the relationship between the 5's in 125,543

Hunter-Best [27]

Answer:

thousand's, and hundreds.

Step-by-step explanation:

the first 5 is in the thousands place, and the second 5 is in the hundreds place.

hope this helped :)

5 0

3 years ago