Answer:
The weight of the block that Katie has is 16 1/3 pounds
Step-by-step explanation:
<u>Katie has: 4 full cement blocks and 4/6 (or 2/3 ) of the normal size of a cement block</u>
For one full block, it weighs 3 2/4 ( or 1/2) pounds, if you want to find the answer of the question, you need to multiply the weight with the cement blocks that Katie have.
<u>First do the four full cement blocks:</u>
4 * 3 2/4 = ?
4 * 14/4 = ?
Cancel the 4 that is being multiplied and the 4 that is being divided by 14.
= 14.
<u>Now do the 4/6 (or 2/3) cement block:</u>
2/3 * 3 2/4 = ?
2/3 * 14/4 = ?
Multiply the fractions together:
= 28/12
= 2 1/3
<u>Finally, you add up the full blocks and the 2/3 cement block to get your answer:</u>
2 1/3 + 14 = 16 1/3
The weight of the block that Katie has is 16 1/3 pounds
I think it would be (D. 88)
~Hope This Helped~
Hello!
6.
Since the area is that of a square, you know that all side lengths are the same.
Area is base times height (A = bh), but since base and height are the same for a square, you get the formula A = a².




The length of the side of a square with an area of 144 in² is
12 in.
7.
Rational number.
8.
This is a right triangle; use the Pythagorean Theorem to find missing lengths of right triangles. Pythagorean Theorem: a² + b² = c², where c is the hypotenuse of the triangle.
Plug in your leg lengths:
a² + b² = c²
8² + x² = 21²
64 + x² = 441
x² = 377
x = 19.4
Answer:
40951
Step-by-step explanation:
Using the principles of inclusion - Exclusion
Where C(n,r)=n!/(n-r)!r!
Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000
Total Number of elements in each pair including number repetition of sets is given as
=(1000) × C(5, 2) =10000
Number of elements in each triple of sets is given as
=(100) × C(5, 3) =1000
Number of elements in every four sets
=(10) × C(5, 4)=50
Number of elements in every one set
(1) × C(5, 5)=1
Therefore total number of unique elements=50000-10000+1000-50+1
=40951