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timurjin [86]
3 years ago
14

100 points

Mathematics
1 answer:
tester [92]3 years ago
3 0
X is equal to 1.5. In order to get this you divide each side by 1.2
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8th grade i need help please
Rudik [331]

Answer: 180 degrees

Step-by-step explanation: I think

4 0
3 years ago
Read 2 more answers
A new DVD is available for sale in a store one week after its release. The cumulative revenue, $R, from sales of the DVD in this
AnnyKZ [126]

Solution :

It is given that :

$f'(t) = (350 \ln   t)'$

       $=350(\ln t)'$

        $=\frac{350}{t}$

So, f(5)=350 \ln (5) \approx 563

     $f'(5) = \frac{350}{5}$

              =70

The relative change is then,

$\frac{f'(5)}{f(5)}=\frac{70}{350\ \ln(5)}$

         $=\frac{1}{5\ \ln(5)}$

         $\approx 0.12$

          =12\%

This means that after 5 weeks, the revenue from the DVD sales in $563 with a rate of change of $70 per week and the increasing at a continuous rate of 12% per week.

3 0
3 years ago
1+4=5<br> 2+5=12<br> 3+6=21<br> 8+11=?
MariettaO [177]
Oh, I SEE what da pattern is! =D
You see, like in this problem:
2 + 5 = 12
They did 5 times 2 = 10, plus da 2 in da problem = 12.
Same with 3 + 6 = 21, 6 times 3 = 18, 18 plus da 3 given in da problem = 21.
Just like 1 + 4 = 5, 4 times 1 = 4, plus da 1 in da problem = 5.
SO,
with that strategy, 8 +11 = 96, because 8 times 11 = 88, plus da 8 given in da problem = 96.
I hope I helped! =D
6 0
3 years ago
A line with a slope of –2 passes through the point (–4, 8). What is the equation of the slope-intercept form?
zloy xaker [14]

Answer:

y= -2x

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Given that the slope is -2, m= -2.

subst. m= -2 into the equation:

y= -2x +c

To find the value of c, substitute a coordinate.

When x= -4, y=8,

8= -2(-4) +c

8= 8 +c (expand)

c= 8-8 (-8 on both sides)

c=0 (simplify)

Thus, the equation of the line is y= -2x.

8 0
3 years ago
Can someone solve this for me?
Helga [31]

well, we know it's a rectangle, so that means the sides JK = IL and JI = KL, so

\stackrel{JK}{3x+21}~~ = ~~\stackrel{IL}{6y}\implies 3(x+7)=6y\implies x+7=\cfrac{6y}{3} \\\\\\ x+7=2y\implies \boxed{x=2y-7} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{JI}{6y-6}~~ = ~~\stackrel{KL}{2x+20}\implies 6(y-1)=2(x+10)\implies \cfrac{6(y-1)}{2}=x+10 \\\\\\ 3(y-1)=x+10\implies 3y-3=x+10\implies \stackrel{\textit{substituting from the 1st equation}}{3y-3=(2y-7)+10} \\\\\\ 3y-3=2y+3\implies y-3=3\implies \blacksquare~~ y=6 ~~\blacksquare ~\hfill \blacksquare~~ \stackrel{2(6)~~ - ~~7}{x=5} ~~\blacksquare

5 0
1 year ago
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