All categories

3 years ago

100 points

Mathematics

1 answer:

tester [92]3 years ago

3 0

X is equal to 1.5. In order to get this you divide each side by 1.2

You might be interested in

Suppose g (x) is increasing and concave up everywhere and g(A)=7, gprime(A)=13, h=.01

rewona [7]

First we need a point (x,y) : (A, 7)
Now slope (from f'(A)) = 15 
Next, the equation (using point slope formula) 

y - 7 = 15 (x -A) 
y = 15 (x - A) + 7 

Now in the x spot we put 'A-.01' 
y = 15 ( A - .01 - A) +7= 15(-.01) +7 = -.15+ 7 = 6.85
hope this helps

8 0

3 years ago

Evaluate the expression3+(a+4)(8-b) when a = 5 and b = 6

castortr0y [4]

Answer:

Step-by-step explanation:

3+(a+4)(8-b)

3+(5+4)(8-6)

3+(9)(2)

3+18

8 0

3 years ago

A line which has an undefined slope is _____.

erastovalidia [21]

Answer:

c, vertical

Step-by-step explanation:

blablablablablanlabla

5 0

3 years ago

Read 2 more answers

The height of a tennis ball tossed into the air is modeled by h(x) = 40x â€" 16x 2, where x is elapsed time in seconds. During w

egoroff_w [7]

The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

Given that,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

We have to determine,

During what time interval will the tennis ball be at least 15 feet above the ground?

According to the question,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

Then,

When the tennis ball be at least 15 feet above the ground,

$h(x) = 15$

Substitute the value of h(x) in the equation,

$\rm h(x) = 40x - 16x^2\\\\ 15 = 40x - 16x^2\\\\ 16x^2-40x+15=0$

Factorize the equation for finding the time interval will the tennis ball be at least 15 feet above the ground is,

$\rm 16x^2-40x+15= 0\\\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2-4 \times 16 \times 15}}{2 \times 16}\\\\x = \dfrac{-(-40)\pm \sqrt{1600- 960}}{32}\\\\x = \dfrac{40\pm \sqrt{640}}{32}\\\\x = \dfrac{40 + 25.29}{32} \\\\x = \dfrac{40 + 25.29}{32} \ and \ x = \dfrac{40 - 25.29}{32}\\\\x = \dfrac{65.29}{32} \ and \ x = \dfrac{14.71}{32}\\\\x = 2.04 \ and \ x = 0.45$

Hence, The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

For more details about Inequality refer to the link given below.

brainly.com/question/17177510

7 0

3 years ago

Fast as possible 1. What is the difference between 23+ 322−42 and 32+ 222−52+3?

dezoksy [38]

Answer:

109

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers