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ziro4ka [17]
3 years ago
6

What’s is the correct answer for this?What is the measurement of BC?

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer:

5

Step-by-step explanation:

use the pythogorean relationship to get the answer.

this type of relationship is used only on right angled triangles.

example: 5  12  13

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What is (5x-2)(4x^2 -3x-2)
Ronch [10]
Answer: 20x^3 - 23x^2 - 4x + 4

Explanation:

Use distributive property:

(5x-2)(4x^2 - 3x-2)
= 20x^3 - 15x^2 - 10x - 8x^2 + 6x + 4
= 20x^3 - 23x^2 - 4x + 4
8 0
3 years ago
Read 2 more answers
Please explain as well 3x+5y=21 4x-2y=-244x−2y=−24
hodyreva [135]

Step-by-step explanation:

3x + 5y = 21 * (-4) •••••• -12x -20y = -84 (a)

4x - 2y = -24 * (3) •••••• 12x -6y = -72 (b)

(a) + (b)

-26y = -156

y = 6

3x + 5 * 6 = 21

3x = 21 - 30

3x = -9

x = -3

3 0
3 years ago
−2x=x^2−6
Iteru [2.4K]

Step-by-step explanation:

Example 1

Solve the equation x3 − 3x2 – 2x + 4 = 0

We put the numbers that are factors of 4 into the equation to see if any of them are correct.

f(1) = 13 − 3×12 – 2×1 + 4 = 0 1 is a solution

f(−1) = (−1)3 − 3×(−1)2 – 2×(−1) + 4 = 2

f(2) = 23 − 3×22 – 2×2 + 4 = −4

f(−2) = (−2)3 − 3×(−2)2 – 2×(−2) + 4 = −12

f(4) = 43 − 3×42 – 2×4 + 4 = 12

f(−4) = (−4)3 − 3×(−4)2 – 2×(−4) + 4 = −100

The only integer solution is x = 1. When we have found one solution we don’t really need to test any other numbers because we can now solve the equation by dividing by (x − 1) and trying to solve the quadratic we get from the division.

Now we can factorise our expression as follows:

x3 − 3x2 – 2x + 4 = (x − 1)(x2 − 2x − 4) = 0

It now remains for us to solve the quadratic equation.

x2 − 2x − 4 = 0

We use the formula for quadratics with a = 1, b = −2 and c = −4.

We have now found all three solutions of the equation x3 − 3x2 – 2x + 4 = 0. They are: eftirfarandi:

x = 1

x = 1 + Ö5

x = 1 − Ö5

Example 2

We can easily use the same method to solve a fourth degree equation or equations of a still higher degree. Solve the equation f(x) = x4 − x3 − 5x2 + 3x + 2 = 0.

First we find the integer factors of the constant term, 2. The integer factors of 2 are ±1 and ±2.

f(1) = 14 − 13 − 5×12 + 3×1 + 2 = 0 1 is a solution

f(−1) = (−1)4 − (−1)3 − 5×(−1)2 + 3×(−1) + 2 = −4

f(2) = 24 − 23 − 5×22 + 3×2 + 2 = −4

f(−2) = (−2)4 − (−2)3 − 5×(−2)2 + 3×(−2) + 2 = 0 we have found a second solution.

The two solutions we have found 1 and −2 mean that we can divide by x − 1 and x + 2 and there will be no remainder. We’ll do this in two steps.

First divide by x + 2

Now divide the resulting cubic factor by x − 1.

We have now factorised

f(x) = x4 − x3 − 5x2 + 3x + 2 into

f(x) = (x + 2)(x − 1)(x2 − 2x − 1) and it only remains to solve the quadratic equation

x2 − 2x − 1 = 0. We use the formula with a = 1, b = −2 and c = −1.

Now we have found a total of four solutions. They are:

x = 1

x = −2

x = 1 +

x = 1 −

Sometimes we can solve a third degree equation by bracketing the terms two by two and finding a factor that they have in common.

6 0
3 years ago
Read 2 more answers
Can someone please help me
Nikolay [14]

Answer:

B

Step-by-step explanation:

x²+2x=19 add 1 to both sides which gives you x²+2x+1=20

x²+2x+1 is the same as (x+1)²

Therefore (x+1)²=20

6 0
3 years ago
√20/125 answer in simpleset form<br>​
grigory [225]

Answer:

.4!

Step-by-step explanation:

first you divide 20 by 125 and get .16

then you take the square root of .16 and get .4

4 0
3 years ago
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