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Darina [25.2K]
3 years ago
14

Bentley is going to invest $98,000 and leave it in an account for 7 years. Assuming

Mathematics
1 answer:
den301095 [7]3 years ago
4 0

Answer:

The rate of interest for compounded daily is 2.1 6

Step-by-step explanation:

Given as :

The principal investment = $ 98,000

The Time period for investment = 7 years

Let The rate of interest compounded daily = R %

The Amount at the end up = $ 114,000

<u>From compounded method</u>

Amount = Principal × (1+\dfrac{rate}{365\times 100})^{365\times Time}

Or, $ 114,000 = $ 98,000  × (1+\dfrac{R}{365\times 100})^{365\times 7}

Or, \frac{114000}{98000} = (1+\dfrac{R}{36500})^{2555}

or, 1.16326 = (1+\dfrac{R}{36500})^{2555}

or, (1.16326)^{\frac{1}{2555}} = 1 + \frac{R}{36500}

1.00005919 - 1 =  \frac{R}{36500}

or, 0.00005919 =  \frac{R}{36500}

∴ R =  0.00005919 × 365000 = 2.16

Hence the rate of interest for compounded daily is 2.1 6   Answer

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If a fair coin is flipped 15 times, what is the probability that there are more heads than tails?
ludmilkaskok [199]

Answer:

The probability that there are more heads than tails is equal to \dfrac{1}{2}.

Step-by-step explanation:

Since the number of flips is an odd number, there can't be an equal number of heads and tails. In other words, there are either

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Let the event that there are more heads than tails be A. \lnot A (i.e., not A) denotes that there are more tails than heads. Either one of these two cases must happen. As a result, P(A) + P(\lnot A) = 1.

Additionally, since this coin is fair, the probability of getting a head is equal to the probability of getting a tail on each toss. That implies that (for example)

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Due to this symmetry,

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In other words P(A) = P(\lnot A).

Combining the two equations:

\left\{\begin{aligned}&P(A) + P(\lnot A) = 1 \cr &P(A) = P(\lnot A)\end{aligned}\right.,

P(A) = P(\lnot A) = \dfrac{1}{2}.

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This conclusion can be verified using the cumulative probability function for binomial distributions with \dfrac{1}{2} as the probability of success.

\begin{aligned}P(A) =& P(n \ge 8) \cr =& \sum \limits_{i = 8}^{15} {15 \choose i} (0.5)^{i} (0.5)^{15 - i}\cr =& \sum \limits_{i = 8}^{15} {15 \choose i} (0.5)^{15}\cr =& (0.5)^{15} \left({15 \choose 8} + {15 \choose 9} + \cdots + {15 \choose 15}\right) \cr =& (0.5)^{15} \left({15 \choose (15 - 8)} + {15 \choose (15 - 9)} + \cdots + {15 \choose (15 - 15)} \right) \cr =& (0.5)^{15} \left({15 \choose 7} + {15 \choose 6} + \cdots + {15 \choose 0}\right)\end{aligned}

\begin{aligned}\phantom{P(A)} =& \sum \limits_{i = 0}^{7} {15 \choose i} (0.5)^{15}\cr =& P(n \le 7) \cr =& P(\lnot A)\end{aligned}.

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