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3 years ago

The angles of two pentagons are all equal to 108°. The length of one side of each pentagon measures 11 cm.

Mathematics

1 answer:

max2010maxim [7]3 years ago

3 0

There is not enough information to determine whether the pentagons are congruent.

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Is Figure 1 similar to Figure 2?

tamaranim1 [39]

Answer:

no figure 1 isn't similar to figure 2

Step-by-step explanation:

because its sides aren't the same numbers nor do the numbers correlate with the numbers in figure one its 2 different numbers

6 0

3 years ago

Light travels about 186,000 mi/s, the function d(t)=186,000 gives the distance in miles that light travels in T seconds , how fa

I am Lyosha [343]

Light travels 5,580,000 mi/s in thirty seconds

4 0

3 years ago

3 ounces of cinnamon cost $2.40. There are 16 ounces in 1 pound how much the cinnamon cost per pound

faltersainse [42]

16 ounces in a pound
2.40 for 3 ounces
16 divided by 3 = 5.333
$2.40 * 5.333 =$
12.8
Approx $12.80 for 1 pound of cinnamon

3 0

3 years ago

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

Read 2 more answers

16 is what percent of 80

Vsevolod [243]

Answer:

your answer is 20%

Step-by-step explanation:

16/80 = .2 = 20%

7 0

3 years ago