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AlekseyPX
3 years ago
13

What should not be used to support a scaffold because they could collapse, sending the structure to the ground?

Physics
1 answer:
uranmaximum [27]3 years ago
5 0

Answer:

Cinder blocks

Explanation:

From safety training guides, whenever there is inadequate support, poor

construction, or a movement in the components of the scaffold such as the coupler as well as the base upon which the scaffold structure is built, there will be a great danger of collapse.

In light of this safety rule, Cinder blocks such as sandcrete blocks, bricks e.t.c shouldn't be used to support scaffold because they have a high tendency of being crushed under load

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Deffense [45]
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3 years ago
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A particle with a charge of +4.0 μC has a mass of 5.0 g. What magnitude electric field directed upward will exactly balance the
aleksley [76]

Answer:

E = 12262 V/m

Explanation:

given,

Charge of the particle, q = +4.0 μC

mass of the ball, m = 5 g

Electric field, E = ?

Force due to weight

F = m g

Force due to electric field

F =q E

To balance the weight of particle both the forces must be equal

Electric field exerted on the ball will be equal to

m g = q E

E = \dfrac{m\ g}{q}

E = \dfrac{5\times 10^{-3}\times 9.81}{4\times 10^{-6}}

E = 12262 V/m

Hence, the electric field acting in the particle is equal to E = 12262 V/m

3 0
3 years ago
Normal force is exerted _____to the surface of an object.
Elanso [62]

The normal force is always (underline, bold) is always perpendicular to the surface an object is sitting on. If the object is on an inclined plane, then the normal will not be vertical but it will be perpendicular to the angle of the incline.

The diagram below (left) shows a normal force (GH) that is not vertical, but it is perpendicular to the surface. The object on the right is the more usual normal a mass on a table top.

The vertical line on the right is the normal and it points up.

3 0
3 years ago
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The velocity of the transverse waves produced by an earthquake is 8.9 km/s, and that of the longitudinal waves is 5.1 km/s. A se
Brrunno [24]

Answer: The distance is 723.4km

Explanation:

The velocity of the transverse waves is 8.9km/s

The velocity of the longitudinal wave is 5.1 km/s

The transverse one reaches 68 seconds before the longitudinal.

if the distance is X, we know that:

X/(9.8km/s) = T1

X/(5.1km/s) = T2

T2 = T1 + 68s

Where T1 and T2 are the time that each wave needs to reach the sesmograph.

We replace the third equation into the second and get:

X/(9.8km/s) = T1

X/(5.1km/s) = T1 + 68s

Now, we can replace T1 from the first equation into the second one:

X/(5.1km/s) = X/(9.8km/s) + 68s

Now we can solve it for X and find the distance.

X/(5.1km/s) - X/(9.8km/s) = 68s

X(1/(5.1km/s) - 1/(9.8km/s)) = X*0.094s/km= 68s

X = 68s/0.094s/km = 723.4 km

6 0
4 years ago
Please help on this one?
Nonamiya [84]

30 or c because 60-30=30

3 0
4 years ago
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