All categories

4 years ago

Jen pushed a box for a distance of 80m with 20 N of force. How much work did she do?

Physics

2 answers:

DENIUS [597]4 years ago

8 0

Work = force x distance
Work = 20 N x 80m
Work = 1600 n-m or 1600 joules
Hope this helps!

mel-nik [20]4 years ago

7 0

Answer:

The work done is 1600 J.

Explanation:

Given that,

Distance = 80 m

Force = 20 N

We need to calculate the work done

The work done is equal to the product of the force and displacement.

Using formula of work done

$W =F\cdot d$

Where, F = force

d = displacement'

Put the value into the formula

$W = 20\times80$

$W = 1600\ N-m=1600\ J$

Hence, The work done is 1600 J.

You might be interested in

Two concentric circular loops of wire lie on a tabletop, one inside the other. The inner wire has a diameter of 20.0 cm and carr

Harrizon [31]

Answer:

Explanation:

Magnetic field due to circular wire at the center = μ₀ I / 2 r

I is current and r is radius . μ₀ = 4π x 10⁻⁷.

field B₁ due to inner loop

B₁ = 4π x 10⁻⁷ x 12 / 2 x .20

= 376.8 x 10⁻⁷

Field due to outer loop

B₂ = 4π x 10⁻⁷ x I / 2 x .30

For equilibrium

B₁ = B₂

376.8 x 10⁻⁷ = 4π x 10⁻⁷ x I / 2 x .30

I = 18 A.

The direction should be opposite to that in the inner wire . It should be anti-clockwise.

4 0

3 years ago

An optical telescope is an instrument that collects and _____.

tresset_1 [31]

An optical telescope is an instrument that collects and enlarges objects from a distance. Hope this helps. Hope this helps. (∩︵∩)
(｡◕‿◕｡)

4 0

3 years ago

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an elect

klio [65]

Complete Question

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?

Answer:

The magnetic field strength is $B= 0.0048 T$

Explanation:

The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

$\Delta V q = \frac{1}{2}mv^2$

Making v the subject

$v = \sqrt{[\frac{2 \Delta V * q }{m}] }$

Where m is the mass of electron

v is the velocity of electron

q charge on electron

$\Delta V$ is the potential difference

Substituting values

$v = \sqrt{\frac{2 * 5.9 *10^3 * 1.60218*10^{-19} }{9.10939 *10^{-31]} }$ f

$= 4.5556 *10^ {7} m/s$

For the electron to move in a circular path the magnetic force[ $F = B q v$ ] must be equal to the centripetal force[ $\frac{mv^2}{r}$ ] and this is mathematically represented as