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Mumz [18]
3 years ago
13

A ferry boat is 2.0 m wide and 4.0 m long. When a truck pulls onto it, the boat sinks 2.00 cm in the water. What is the weight o

f the truck?DENSITY OF WATER IS 1000 Kg/m^3
Physics
1 answer:
Slav-nsk [51]3 years ago
8 0

Answer:

156,800 N

Explanation:

Given: Width = 2.0 m Length = 4.0 m Depth =  2.00 cm. Density of water = 1000 Kg/m³

To find: What is the weight of the truck?

Formula: F = m × 9.8 m/s^2

Solution: Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity, which is 9.8 m/s² on Earth. F is the object's weight in Newtons (N) and m is the object's mass in kilograms.

Firstly, multiply the length, width, and depth.

2.0 × 4.0 × 2.00 = 16

Next, the weight of the truck is found by multiplying the density of water, the result found by multiplying the length, width, and depth, and the formula;

1000 kg/m^3 × 16 × 9.8m/s^2= 156,800

Therefore, the weight of the truck is 156,800 N

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<span>This would be the correct the answer to the following question above.:
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7 0
3 years ago
A gas mixture contains 320mg methane, 175 mg argon, 225 mg nitrogen (N2). The partial pressure of argon at 300K is 12.52 kPa. Wh
svet-max [94.6K]

<u>Answer:</u> The volume and total pressure of the mixture is 0.876 L and 89.36 kPa respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For methane:</u>

Given mass of methane = 320 mg = 0.3 g     (Conversion factor:  1 g = 1000 mg)

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane}=\frac{0.3g}{16g/mol}=0.019mol

  • <u>For argon:</u>

Given mass of argon = 175 mg = 0.175 g

Molar mass of argon = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of argon}=\frac{0.175g}{40g/mol}=0.0044mol

  • <u>For nitrogen:</u>

Given mass of nitrogen = 225 mg = 0.225 g

Molar mass of nitrogen = 28 g/mol

Putting values in equation 1, we get:

\text{Moles of nitrogen}=\frac{0.225g}{28g/mol}=0.0080mol

To calculate the volume of the mixture, we use the equation:

PV = nRT         ......(2)

We are given:

Partial pressure of argon = 12.52 kPa

Temperature = 300 K

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

n = number of moles of argon = 0.0044 moles

Putting values in equation 2, we get:

12.52kPa\times V=0.0044mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 300K\\\\V=\frac{0.0044\times 8.31\times 300}{12.52}=0.876L

Now, calculating the total pressure of the mixture by using equation 2:

Total number of moles = [0.019 + 0.0044 + 0.0080] mol = 0.0314 mol

V= volume of the mixture = 0.876 L

Putting values in equation 2, we get:

P\times 0.876L=0.0314mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 300K\\\\P=\frac{0.0341\times 8.31\times 300}{0.876}=89.36kPa

Hence, the volume and total pressure of the mixture is 0.876 L and 89.36 kPa respectively.

5 0
3 years ago
If Rebecca is traveling at 7 m/s east for 1 hour how much is Rebecca displaced
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Answer:

25.2 km east

Explanation:

The relationship between velocity and displacement is given by:

v=\frac{d}{t}

where

v is the velocity

d is the displacement

t is the time

In this problem, we have:

v=7 m/s east is Rebecca's velocity

t=1 h=60 min=3600 s is the time taken

Re-arranging the equation, we can find Rebecca's displacement:

d=vt=(7 m/s)(3600 s)=25,200 m=25.2 km

and the direction is same as velocity (east)

3 0
3 years ago
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5 0
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deff fn [24]

Answer:

Explanation:

Given

side of square shape a=5\ cm

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\phi =EA\cos \theta

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E=\frac{\sigma }{2\epsilon_0}

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\sigma =0.012\times 8.85\times 10^{-12}

\sigma =2.12\times 10^{-13}\ C/m^2    

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