3 years ago

What are the four steps in the machine cycle?

1 answer:

8 0

Machine cycle. The four steps which the CPU carries out for each machine language instruction: fetch, decode<span>, execute, and store. hope that helped</span>

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Can someone please help me on this

Triss [41]

Answer:

I am on the same question and I’m lost

Explanation:

4 0

3 years ago

Daniel has a bill of 2750 on his credit card. If interest is charged at a rate of 15% p.a., calculate the amount of interest tha

9966 [12]

Answer:

412.5

Explanation:

all you have to do is multiply .15

8 0

3 years ago

Eac of the two Straight Parallel Lines Each of two very long, straight, parallel lines carries a positive charge of 24.00 m C/m.

Cloud [144]

Answer:

The magnitude of the electric field at a point equidistant from the lines is $4.08\times10^{5}\ N/C$

Explanation:

Given that,

Positive charge = 24.00 μC/m

Distance = 4.10 m

We need to calculate the angle

Using formula of angle

$\theta=\sin^{-1}(\dfrac{\dfrac{d}{2}}{2d})$

$\theta=\sin^{-1}(\dfrac{1}{4})$

$\theta=14.47^{\circ}$

We need to calculate the magnitude of the electric field at a point equidistant from the lines

Using formula of electric field

$E=\dfrac{2k\lambda}{r}\times2\cos\theat$

Put the value into the formula

$E=\dfrac{2\times9\times10^{9}\times24.00\times2\times10^{-6}\cos14.47}{2.05}$

$E=408094.00\ N/C$

$E=4.08\times10^{5}\ N/C$

Hence, The magnitude of the electric field at a point equidistant from the lines is $4.08\times10^{5}\ N/C$

6 0

3 years ago

How much force is needed to accelerate a 1,100 kg car at a rate of 1.5 m/s2?

Anna [14]

Assuming there is no force of friction...

F = ma
F = (1300kg)(1.5m/s^2)
F = 1950N
Just multiply mass by acceleration.
1300 x 1.5 = 1950N.

7 0

3 years ago

10. A 90 kg box is sliding across a surface at a constant velocity while experiencing a rightward applied

ANEK [815]

If the box is moving at constant velocity, net force must be zero, so:

F + fr = 0

fr = -F

4 0

3 years ago

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