Question

The Schuller family has five members. Dad is 6ft 2in tall. Mom is 3 inches shorter than Dad, but 2 inches taller than Ivan. Marcia is 5 inches shorter than Ivan, but twice as tall as Sally-Jo. What is the mean height of the Schuller family?

Answer 1

Answer:

62 inches

Step-by-step explanation:

Let x be the height ( in inches ) of Ivan,

∵ Marcia is 5 inches shorter than Ivan,

height of Marcia = x - 5,

Marcia is  twice as tall as Sally-Jo,

height of sally-jo = $\frac{x-5}{2}$

Mom is 2 inches taller than Ivan.

⇒ height of mom = x + 2,

Mom is 3 inches shorter than Dad,

height of dad = x + 2 + 3 = x + 5,

So, mean height of family is,

$\frac{x+x-5+\frac{x-5}{2}+x+2+x+5}{5}$

$=\frac{2x+2x-10+x-5+2x+4+2x+10}{10}$

$=\frac{9x-1}{10}$

According to the question,

x + 5 = 74 ( 1 ft = 12 in )

x = 69

Hence, mean height of the family = $\frac{9\times 69-1}{10}$

$=\frac{620}{10}$

= 62 inches