Answer:
boiling water
Explanation:
boiling water produces more severe burns
Answer:
16.6 mg
Explanation:
Step 1: Calculate the rate constant (k) for Iodine-131 decay
We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.
k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹
Step 2: Calculate the mass of iodine after 8.52 days
Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.
ln I = ln I₀ - k × t
ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day
I = 16.6 mg
Answer:
V₂ = 918.1 cm³
Explanation:
Given data:
Initial volume = 640 cm³
Initial temperature = 100°C (100+273 = 373 K)
Initial pressure = 1490 mmHg (1490 /760 = 1.96 atm)
Final volume = ?
Final temperature = 273 K
Final pressure = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
now we will put the values in formula.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.96 atm × 640 cm³ × 273 K / 373 K × 1 atm
V₂ = 342451.2 atm .cm³ . K / 373 K. atm
V₂ = 918.1 cm³
Answer:
600mL
Explanation:
Molarity of a solution (M) = number of moles (n) ÷ volume (V)
number of moles = mass/molar mass
Molar mass of NaOH = 23 + 16 + 1
= 40g/mol
mole = 30/40
n of NaOH = 0.75mol
Using Molarity = n/V
V = number of moles ÷ molarity
V = 0.75 ÷ 1.25
V = 0.6L
In milliliters (mL), the volume of NaOH will be 0.6 × 1000
= 600mL
