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e-lub [12.9K]
3 years ago
15

If substances and B are both in the solid phase and are at the same energy level, which of the two substances will need to have

more energy transferred in order to change to the liquid phase?Substance A or substance B? Explain your answer.
Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

substance A would change it :)

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D.) black text on a yellow background. There is much more contrast in the colors black and yellow than the other choices.
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Why do they call Cleveland "the mistake by the lake"?
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Mostly because the lake smell really bad and the waters really dirty

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4 years ago
What is the wavelength of radio waves? Which statement is true for a cooling curve? A. It shows how the temperature of the subst
ladessa [460]

Answer:

Most radio waves have wavelengths between 1 mm and 100 km.

A cooling curve shows A. how the temperature of a substance falls as heat is removed.

Explanation:

<em>Radio waves</em> are the longest of all the waves in the electromagnetic spectrum.

Most have wavelengths between 1 mm and 100 km, although there is no upper limit.

Some radio waves have wavelengths of 10 000 km.

A <em>cooling curve</em> (see image below) shows how the temperature of a substance falls as it is cooled.

In Option E., a decrease in temperature would cause an energy <em>loss</em>.

Options B., C., and D. involve the <em>addition of heat</em>.

5 0
4 years ago
Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (
aleksley [76]

<u>Answer:</u> The amount of heat produced by the reaction is -21.36 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]

We are given:

\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol

To calculate the number of moles, we use ideal gas equation, which is:

PV=nRT

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = 0.0831\text{ L. bar }mol^{-1}K^{-1}

T = temperature of the mixture = 25^oC=[25+273]K=298K

Putting values in above equation, we get:

1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol

To calculate the heat released of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

\Delta H_{rxn} = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0
3 years ago
PLEASE HELP ASAP FOR 25 POINTS!! :D
kondaur [170]

the x y axis is tipped so the earth is flat

3 0
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