Hey i hope my answer is helpful i did in my head so im sorry if its wrong−13 13/35
The answer is 13/85. You could find out the answer by doing the reprical multiplication.

Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Hello Srahman1183 i get how adjetated u must be feeling right now having to wait 6 days to get this answer im about to give u but whatever. The relationship between them istheyare both partof the powers of ten, the first 6 is inthe 100 place and the second 6 is in the 10 place, hope this helped