The height of the triangle is 19.596 centimeter, if a right isosceles triangle has an area of 192 square centimeters.
Step-by-step explanation:
The given is,
Area of right isosceles triangle is 192 square centimeters
Step:1
Formula for area of right isosceles triangle is,
............................(1)
Where, a - Sides of triangle
a = h = b
Here, h - Height of triangle
b - Base of triangle
From given,
Area, A = 192 square centimeters
Equation (1) becomes.


= 384

Take square root on both sides,

a = 19.596 centimeters
Height of right isosceles of triangle, a = h = 19.596 centimeters
Result:
The height of the triangle is 19.596 centimeter, if a right isosceles triangle has an area of 192 square centimeters.
C and E, evaluate the numbers outside of the parenthesis to the inside
Ok so 2(4q+3)=4q-14
2.4q=8q
2.3=6
8q+6=4q-14
8q-4q=-14-6
4q=-20
q=-20/4
q=-5
The vertex U' is located at (-4, -5)
<h3>How to determine the location of U'?</h3>
The vertices are given as:
U = (-4, 5)
V = (-6, 2)
The rule of transformation is given as:
Reflection across the x-axis
This is represented as:
(x, y) => (x, -y)
So, we have:
U' = (-4, -5)
Hence, the vertex U' is located at (-4, -5)
Read more about transformation at:
brainly.com/question/11707700
#SPJ1
<u>Complete question</u>
Quadrilateral UVWX is reflected over the x-axis to form quadrilateral U′V′W′X′. If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at
Its the third one im pretty sure