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Scorpion4ik [409]
3 years ago
7

Please help me solve this​

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0
Since AB and QR are equal set them equal and plug in your answer for x for AB

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Find 1 3/5 + 1 1/3 iready
Arisa [49]
20 plus 24
Divided by 15
Which gets you to
44 over 15 or 2 wholes and 14 over 15
5 0
2 years ago
Read 2 more answers
Researchers ask a random sample of 1,001 adults nationwide whether they favor or oppose the legalization of marijuana. Fifty-fiv
natima [27]

Answer:

b. It will decrease by a factor of 2

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The lower end of the interval is given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}}

The upper end of the interval is given by:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}}

The length of the interval is the subtraction of the upper end by the lower end, so it is:

L = 2z\sqrt{\frac{\pi(1-\pi)}{n}}

This means that the length is inverse proportional to the square root of the size of the sample.

So, if the sample size is multiplied by 4, the length of the interval is going to decrease by a factor of 2.

4 0
3 years ago
MATH PLEASE HELP TwT
kaheart [24]

Answer:

The first and the third answer!

Step-by-step explanation:

The slope is NOT -6, it is -3/2 !!

The y intercept is 0

and the last one isn't right bc the slope and intercept is wrong!!!

I hope this helps, tho!! Have an awesome day :D

7 0
3 years ago
Please solve equations by completing square
BlackZzzverrR [31]
x^2-4x+1=0\\
x^2-4x+4-3=0\\
(x-2)^2=3\\
|x-2|=\sqrt3\\
x-2=\sqrt3 \vee x-2=-\sqrt3\\
x=2+\sqrt3 \vee x=2-\sqrt3

x^2+6x-9=0\\
x^2+6x+9-18=0\\
(x+3)^2=18\\
|x+3|=\sqrt{18}=3\sqrt2\\
x+3=3\sqrt2 \vee x+3=-3\sqrt2\\
x=-3+3\sqrt2 \vee x=-3-3\sqrt2\\

x^2+20x+3=0\\
x^2+20x+100-97=0\\
(x+10)^2=97\\
|x+10|=\sqrt{97}\\
x+10=\sqrt{97} \vee x+10=-\sqrt{97}\\
x=-10+\sqrt{97} \vee x=-10-\sqrt{97}

x^2-2x-5=0\\
x^2-2x+1-6=0\\
(x-1)^2=6\\
|x-1|=\sqrt6\\
x-1=\sqrt6 \vee x-1=-\sqrt6\\
x=1+\sqrt6 \vee x=1-\sqrt6
8 0
3 years ago
Find x. (Use pic for more info)
V125BC [204]

Answer:

x=75

Step-by-step explanation:

Hey There!

If you didn't know the exterior angle of a triangle is equal to the sum of the opposite interior angles of a triangle

So essentially what I'm saying is that

2x-5=70+x

step 1 add 5 to each side

-5+5 cancels out

70+5=75

now we have

2x=70+x

step 2 subtract x from each side

x-x cancels out

2x-x=x

we're left with

x=75

8 0
3 years ago
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