Answer=140 fish
200 gallons of water in the first aquarium.
200 gallons of water in the second aquarium.
The first will be for the small fishes.
5 small fish x fish
_____________=__________
10 gallons 200 gallons
cross multiply
10x=1000
divide both sides by 10
x=100 small fish
The first aquarium has 100 small fish.
The second aquarium holds large fish.
8 large fish x fish
____________=___________
40 gallons 200 gallons
cross multiply
40x=1600
divide both sides by 40
x=40 large fish
The second aquarium has 40 large fish.
100small fish+40 large fish=140 total fish
Answer:
Below.
Step-by-step explanation:
15y + 12x = 18
5y + 4x = 6
The second equations is the first times 3 so they are basically the same.
Infinite Solutions.
2x+ 3y= 12
-6y= 4x-24 Rearranging the second equation:
-4x - 6y = -24 Multiplying the first equation by 2:
4x + 6y = 24
- we see that the last equation is -1 * previous equation.
So there are infinite solutions.
Answer:
i'm pretty sure it's d hope this helps
Step-by-step explanation:
Please upload the question and i will work it out, have a lovely day!
