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anygoal [31]
3 years ago
12

When a substance dissolves, it undergoes a chemical change. a. True b. False

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
7 0


False.

Solubility is not a chemical property but rather it is a physical property. A physical property is one that can be observed or measured and does not change the composition or identity of a substance in the process.

When a substances dissolves, this is a change of its physical state and it is mostly reversible.  For example, salt can dissolve in water to form a solution called brine. This does not alter the chemical nature of salt. When the water evaporates, salt is left behind in its original state or form. In other words, that was a physical change and it was completely reversible.


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It should be wind direction

Explanation:

I hope this helps. Let me know if I am wrong

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Write the nuclear equation to describe the alpha decay of 243 95 Am
motikmotik

Answer:

Here's what I get.

Explanation:

Your unbalanced nuclear equation is:

_{95}^{243}\text{Am} \longrightarrow \, _{x}^{y}\text{Z} +\, _{2}^{4}\text{He}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

  95 = x + 2, so x =   95 - 2 =    93

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Element 93 is neptunium, so the nuclear equation becomes

_{95}^{243}\text{Am} \longrightarrow \, _{93}^{239}\text{Np} + \, _{2}^{4}\text{He}  

7 0
3 years ago
Read 2 more answers
If you obtained 2.50 moles of CuSO4 from the reaction of CuO and H2SO4, but the theoretical yield was 3.19 moles, what was the p
IceJOKER [234]

Answer:

  • 78.4%

Explanation:

Just as context, write the chemical equation and the mole ratios

1) <u>Balanced chemical equation</u>:

  • CuO (s) +  H₂SO₄ (aq) → CuSO₄ (aq) + H₂O (l)

2) <u>Therotetical (stoichiometric) mole ratios</u>:

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You can calculate the percent yield from the amount of CuSO₄ obtained and the theoretical yield

3) <u>Percent yield</u>

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         Percent yield = (actual yield / theoretical yield)×100

  • Theoretical yiedl (given): 3.19 moles CuSO₄

  • Actual yield (given): 2.50 moles CuSO₄

  • Calcualtion:

Substitute the values in the formula:

  • Percent yield = (2.50 moles CuSO₄ / 3.19 moles CuSO₄)×100 = 78.4%

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It doesn't exactly mean anything, but it does describe the second group of elements, the Alkali Earth Metals.

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