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lys-0071 [83]
2 years ago
11

Which characteristic of money explains why an old dollar is worth as much as a crisp, new dollar?

Chemistry
1 answer:
raketka [301]2 years ago
5 0

The characteristic is uniformity.

<h3>Uniformity of money</h3>

Money is said to be uniform because irrespective of the nature it exists, the same amount must have the same purchasing power.

For example, a dollar in paper form and a dollar in coin form must be able to buy the same 1 dollar worth of goods.

Thus, a dollar bill, irrespective of its age, has the same purchasing power as a new, crisp dollar bill.

More on uniformity of money can be found here: brainly.com/question/17039370

#SPJ1

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when 824 J of heat is added to 9 grams of oil at 30°c , the temperature increases to 87°C. what is the specific heat of the oil
sattari [20]

Answer:

c = 1.61 j/g.°C

Explanation:

Given data:

Mass of oil = 9 g

Heat added = 824 j

Initial temperature =  30°C

Final temperature = 87°C

Specific heat of oil = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - final temperature

ΔT = 87°C - 30°C

ΔT = 57 °C

Q = m.c. ΔT

824 j = 9 g × c ×  57 °C

824 j = 513 g. °C × c

c = 1.61 j/g.°C

5 0
3 years ago
When a sample of aqueous hydrochloric acid was neutralized with aqueous sodium hydroxide in a calorimeter, the temperature of 10
Annette [7]
<span>6.50x10^3 calories. Now we have 4 pieces of data and want a single result. The data is: Mass: 100.0 g Starting temperature: 25.0°C Ending temperature: 31.5°C Specific heat: 1.00 cal/(g*°C) And we want a result with the unit "cal". Now you need to figure out what set of math operations will give you the desired result. Turns out this is quite simple. First, you need to remember that you can only add or subtract things that have the same units. You may multiply or divide data items with different units and the units can combine or cancel each other. So let's solve this: Let's start with specific heat with the unit "cal/(g*°C)". The cal is what we want, but we'ld like to get rid of the "/(g*°C)" part. So let's multiply by the mass: 1.00 cal/(g*°C) * 100.0 g = 100.0 cal/°C We now have a simpler unit of "cal/°C", so we're getting closer. Just need to cancel out the "/°C" part, which we can do with a multiplication. But we have 2 pieces of data using "°C". We can't multiply both of them, that would give us "cal*°C" which we don't want. But we need to use both pieces. And since we're interested in the temperature change, let's subtract them. So 31.5°C - 25.0°C = 6.5°C So we have a 6.5°C change in temperature. Now let's multiply: 6.5°C * 100.0 cal/°C = 6500.0 cal Since we only have 3 significant digits in our least precise piece of data, we need to round the result to 3 significant figures. 6500 only has 2 significant digits, and 6500. has 4. But we can use scientific notation to express the result as 6.50x10^3 which has the desired 3 digits of significance. So the result is 6.50x10^3 calories. Just remember to pay attention to the units in the data you have. They will pretty much tell you exactly what to add, subtract, multiply, or divide.</span>
4 0
3 years ago
5. For career day, Maria invited her uncle, an astronomer, to speak to her class about his boyhood
Sphinxa [80]

Answer:

B. Distance from earth. I'm pretty sure. From what I learned it should be that.

5 0
3 years ago
How many grams of LiNO2 are required to make 250 mL of 0.75 Molarity solution?
Katarina [22]

Answer:

159 g OF LiNO2 WILL BE USED TO MAKE 0.25 L OF 0.75 M SOLUTION.

Explanation:

How many grams of LiNO2 are required to make 250 mL of 0.75 M?

First calculate the molarity in mol per dm3

0.75 M of LiNO2 reacts in 250 mL = 250 /1000 L volume

0.75 M = 0.25 L

In 1 L, the molarity of LiNO2 will be:

= (0.75 * 1/ 0.25) M

= 3 mol/dm3 of LiNO2

Next is to calculate the molarity in g/dm3:

Molarity in mol/dm3 = molarity in g/dm3 / RMM.

RMM of LiNO2

(Li = 7 , N =14 , 0 = 16)

RMM = ( 7 + 14 + 16 * 2) = 53 g/mol

Molarity in mol/dm3 =  Molarity in g/dm3 / RMM

Molarity in g/dm3 = Molarity in mol/dm3 * RMM

Molarity in g/dm3 = 3 * 53

Molarity in g/dm3 = 159 g/dm3.

So therefore, to make 250 mL of 0.75 M of LiNO2, we use 159 grams of LiO2.

8 0
3 years ago
50 atoms, 15 were isotope A, 30 were isotope B, and 5 were isotope C, which isotope would be the most abundant?
Juliette [100K]

The most abundant isotope among the given Isotopes will be Isotope B

<h3>How to calculate percentage abundance of isotopes ?</h3>

To calculate the percent abundance of each isotope in a sample of an element, we usually divide the number of atoms of a particular isotope by the total number of atoms of all isotopes of that element and then multiply the result by 100.

  • For  Isotope A ;

% Abundance =  15/50 x 100

                        =  30 %

  • For  Isotope B ;

% Abundance =  30/50 x 100

                        =  60 %

  • For  Isotope A ;

% Abundance =  5/50 x 100

                        =  10 %

Hence, The most abundant isotope among the given Isotopes will be Isotope B.

Learn more about isotopes here ;

brainly.com/question/12955625

#SPJ1

5 0
2 years ago
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