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aksik [14]
2 years ago
5

What is the empirical formula for CaCo3?*

Chemistry
1 answer:
GalinKa [24]2 years ago
5 0

This problem is requiring the empirical formula for CaCO₃, which is its molecular formula, and turns out to be equal, this is A. CaCO3 according to the following:

<h3>Empirical formulas:</h3><h3 />

In chemistry, molecular formulas show both the actual type and number of atoms in a chemical compound, based on the elements across the periodic table and the subscripts standing for the number of atoms in the compound.

However, the empirical formula is a reduced expression of the molecular one, which shows the minimum number of atoms in a compound after simplifying to the smallest whole numbers.

In such a way, since the given compound is CaCO₃ and both Ca and C have a one as their subscript, it is not possible to simplify any further and therefore the empirical formula equals the molecular one this time, making the answer to be A. CaCO3.

Learn more about empirical formulas: brainly.com/question/1247523

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Kisachek [45]

Answer:

Gravity or the gravitational force is defined as the force of attraction occurring between all states of matter. The sun’s gravity, mass, and radius plays a crucial role in the properties of the Sun.

Explanation:

The gravity of an object can be determined using the formula:

\text{g}&=\frac{\text{GM}}{\text{R}^{2} }}

Now, according to the question, the mass of the sun is halved, which will be written as:

\text{g}&=\frac{\text{G}\frac{\text{M}}{2}}{\text{R}^{2} }}

Thus, according to the equation, the mass of an object is directly proportional to the gravitational field. since, the mass of the Sun is reduced to half, the gravity of the Sun will be halved.

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2 years ago
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Need science help (screenshot included)
Dima020 [189]

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C. True. The whole solar system moves around the galaxy.

D. True. If a planet’s gravity is not strong enough, the molecules in its atmosphere will have enough kinetic energy to escape into space.

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6 0
3 years ago
How many moles of aluminum oxide al2o3 are in a sample with a mass of 204.0
erik [133]

Answer:

2 moles

Explanation:

Let us first start by calculating the molecular mass of Al₂O₃.

The mass of a mole of any compound is called it's molar mass. 1 molar mass 6.02 X 10²³, or Avogadro's number, of compound entities.

Say, 1 mole of Al₂O₃ has 6.02 X 10²³ of Al₂O₃ molecules/atoms. It also has 2*6.02 X 10²³ number of Al atoms and 3*6.02 X 10²³ number of O atoms.

Molecular mass of Al : 26.981539 u

Molecular mass of O: 15.999 u

Therefore, molecular mass of Al₂O₃ is:

= (2*26.981539) + (3*15.999) u

= 101.960078 u

This can be approximated to 102 u.

1mole weighs 102 u

So, 2moles will weigh 2*102 = 204 u

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2 years ago
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The arsenic in a 1.223 g sample of a pesticide was converted to H3AsO4 by suitable treatment. The acid was then neutralized, and
Vladimir79 [104]

Answer:

5.471% As₂O₃ in the sample.

Explanation:

<em>...the reaction is: Ag+ + SCN- => AgSCN(s) Calculate the percent As2O3 in the sample. (F.W. As2O3 = 197.84 g/mol).</em>

<em />

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<em>Moles of Ag⁺ in the precipitate:</em>

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0.0020294 moles Ag⁺ * (1mol As / 3 moles Ag⁺) = 6.765x10⁻⁴ moles AsO₄

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6.765x10⁻⁴ moles AsO₄ * (1 mol As₂O₃ / 2 mol AsO₄) =

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Percent is:

0.0669g As₂O₃ / 1.223g sample * 100 =

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<em />

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