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aksik [14]
2 years ago
5

What is the empirical formula for CaCo3?*

Chemistry
1 answer:
GalinKa [24]2 years ago
5 0

This problem is requiring the empirical formula for CaCO₃, which is its molecular formula, and turns out to be equal, this is A. CaCO3 according to the following:

<h3>Empirical formulas:</h3><h3 />

In chemistry, molecular formulas show both the actual type and number of atoms in a chemical compound, based on the elements across the periodic table and the subscripts standing for the number of atoms in the compound.

However, the empirical formula is a reduced expression of the molecular one, which shows the minimum number of atoms in a compound after simplifying to the smallest whole numbers.

In such a way, since the given compound is CaCO₃ and both Ca and C have a one as their subscript, it is not possible to simplify any further and therefore the empirical formula equals the molecular one this time, making the answer to be A. CaCO3.

Learn more about empirical formulas: brainly.com/question/1247523

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What is it called when scientists write out a compound such as two hydrogen and one oxygen? PLEASE HELP
schepotkina [342]
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3 years ago
Explain why the quantum number set (3, 2, 3, -½) is not possible for an electron in an atom
Triss [41]
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3 years ago
What do Potassium and Krypton have in common and what are their differences based on their location on the periodic table?
andreev551 [17]

Common based on their location in Periodic Table;

Potassium has an atomic number 19. Its electronic configuration is as follow;

                                       1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹

And Krypton has an atomic number of 36. Its electronic configuration is as follow;

                                1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶

It is concluded that both Potassium and Krypton has their valence electrons in 4rth shell or they have same Principle Quantum Number.

Difference based on their location in Periodic Table;

As observed in electronic configuration Potassium has one valence electron in its valence shell (i.e. 4s¹) while, Krypton has eight valence electrons in its valence shell (i.e. 4s², 4p⁶). Therefore, they are different in the number of valence electrons.

6 0
3 years ago
Write balanced chemical equation for the reactions used to prepare each of the following compounds from the given starting mater
creativ13 [48]

Explanation:

A balanced chemical equation is defined as the one that contains same number of atoms on both reactant and product side.

Whereas a chemical reaction that brings change in oxidation state of the reacting species is known as a redox reaction.

When there occurs decrease in oxidation number of an element then it shows the element has been reduced. And, if there occurs an increase in oxidation state of an element then it means the element has been oxidized.

(a)   The reaction between nitrogen and hydrogen to form ammonia will be as follows.

                N_{2} + 3H_{2} \rightarrow 2NH_{3}

So here, oxidation state of nitrogen is changing from 0 to -3. Whereas oxidation state of hydrogen is changing from 0 to +3.

Reaction between ammonia and nitric acid will be as follows.

            NH_{3} + HNO_{3} \rightarrow NH_{4}NO_{3}

Since, it is a combination reaction. Therefore, no change in oxidation state of reacting species is taking place.

(b)  Reaction for conversion of liquid bromine to hydrogen bromide is as follows.

            H_{2}(g) + Br_{2}(l) \rightarrow 2HBr(g)

Here, oxidation state of hydrogen is changing from 0 to +1. Therefore, oxidation of hydrogen is taking place. On the other hand, oxidation state of bromine is changing from zero to -1. Therefore, reduction of bromine is taking place.

(c)   Reaction between Zn and S will be as follows.

               Zn(s) + S(s) \rightarrow ZnS(s)    

Here, oxidation state of zinc is changing from 0 to +2. Hence, oxidation of zinc is taking place.

Oxidation state of sulfur is changing from 0 to -2. Therefore, reduction of sulfur is taking place.

7 0
3 years ago
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