do you need to include the wiggle infront of the first bracket? if not;
(x+1) ÷ [(x^2+2) x (2x-3dx)]
x^2 x 2x = 2x^3
x^2 x -3dx = -3dx^3
2 x 2x = 4x
2 x -3dx = - 6dx
i cant find a way to make it equal 0 so i think the answer is just
x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction
Answer:
2. Equivalent
4. Denominator
Step-by-step explanation:
2. To subtract unlike fractions, rewrite them as <u><em>Equivalent</em></u> fractions with the same denominator. This is true because when we want to add or subtract fractions with different denominators, we can multiply them until they have the same denominator, which allows us to easily subtract.
4. Fractions with equal numerators and <em><u>Denominators</u></em> are equivalent to 1. This is also true, since 4/4 is a whole number, and that is the case with any fraction that has the same numerator and denominator
Hope this helps! :D
The expression would show three sevenths of y minus four.
Answer:
its option b
9:10
..........................
