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DerKrebs [107]
4 years ago
9

(4-2i).(6-3i) / (1-i).(1+i)

Mathematics
2 answers:
timofeeve [1]4 years ago
7 0

Answer:

9 - 12i

Step-by-step explanation:

Noting that i² = - 1

Expand the factors on the numerator and denominator

(4 - 2i)(6 - 3i) = 24 - 12i - 12i + 6i² = 24 - 24i - 6 = 18 - 24i

(1 - i)(1 + i) = 1 + i - i - i² = 1 + 1 = 2

The division reduces to

\frac{18-24i}{2}

= \frac{18}{2} - \frac{24}{2} i

= 9 - 121i

AlexFokin [52]4 years ago
6 0

Answer:

2i + 6

Step-by-step explanation:

4-2 = 2

6-3 = 3

2 * 3 = 6

2i

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