A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
B
Step-by-step explanation:
1+1=2
But 2x has to stay the same
To mix cleaner and water you need to divide the bucket's capacity into 4.It's easy in this case as gallon is divided into quarts (1 gallon = 4 quarts).We know that one part will be cleaner, it means that you will need to use 1 quart of the cleaner.
hope thats right
Answer:
x > 8
Step-by-step explanation:
I hope this helps you out!
The cost of the ride varies by however many miles is driven, however the charging rate stays the same no matter how long the ride is. In the expression 0.20m + 2.00 , 2.00 is the constant as it stays the same, and 0.20 is the coefficient as is varies with however many miles are driven.
