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3 years ago

If q is between 0 degrees and 90 degrees and tan deta =7/8 find cosine deta

Mathematics

1 answer:

sertanlavr [38]3 years ago

4 0

Answer:

question is unclear

Step-by-step explanation:

I dont know

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The hypotenuse of a right triangle is four times the length of one of the legs. The length of the other leg is 1500⎯⎯⎯⎯⎯⎯⎯⎯√ fee

Mrac [35]

Answer:

Step-by-step explanation:

So this is just playing with the pythagorean theorem

a^2 + b^2 = c^2 with a and b as legs and c as the hypotenuse.

Let's say a is equal to 1500 so then c is 4 times b

1500^2 + b^2 = (4b)^2 Now we just treat this like a normal algebraic expression

2,250,000 = 16b^2 - b^2

2,250,000 = 15b^2

150,000 = b^2

sqrt(150,000) = b

100sqrt(15) = b

You can check this now.

1500^2 + sqrt(150,000)^2 = c^2

sqrt(2,250,000 + 150,000) = c

sqrt(2,400,000) = c

400sqrt(15) = c Which fits the requirement of c = 4b

7 0

3 years ago

(0.053) (0.578)<br> Multiply the numbers

Crazy boy [7]

Answer:

If you multiply the numbers you will get

0.030634

5 0

3 years ago

WhAt is the square root of 2 times the square root of 2

Papessa [141]

Answer:

2 is the answer

Step-by-step explanation:

its like

(square root 2)^2

{square root and whole square is cancelled and 2 is the answer}

3 0

3 years ago

Write a variable expression for 4 fewer than a number s.

rjkz [21]

S - 4

s minus 4 is the answer. s is the number and this is 4 fewer than s. Hope this helps.

8 0

2 years ago

Find equation of set of points pieces that its distance from the point 3, 4, -5 and -2, 1, 4 are equal.

Gnesinka [82]

Answer:

Step-by-step explanation:

Suppose we a point $P(x,y,z)$ such that its distance from either the point $A(3,4,-5)$ or $B(-2,1,4)$ is the same.

Using this information we can formula:

distance AP = distance BP

first, let's find the distance from AP, using the distance formula.

$r = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}$

$AP = \sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2}$

similarly, we can find the distance BP

$BP = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

since both distances are exactly the same we can equate them

$AP = BP$

$\sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2} = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

we can simplify it a bit squaring both sides, and getting rid of the subscripts.

$(3 - x)^2 + (4 - y)^2 + (-5 - z)^2 = (-2 - x)^2 + (1 - y)^2 + (4 - z)^2$

what we have done here is formulated an equation which consists of any point P that will have the same distance from (3,4,-5) and (-2,1,4).

To put it more concretely,

This is the equation of the the plane from that consists of all points (P) from which the distance from both (3,4,-5) and (-2,1,4) are equal.

3 0

2 years ago