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Katarina [22]
3 years ago
6

Heather must choose a number between 55 and 101 that is a multiple of 3, 5, and 9.

Mathematics
1 answer:
yanalaym [24]3 years ago
5 0
M9=<u>63, 72, 81, 90, 99</u>
M5 П M9=<u>90</u>
M5 П M9 П M3=<u>90</u>

<em>Answer:90</em>
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The area of Erin's circle to the nearest hundredth is 50.24 in².

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A circle is a bounded figure which points from its center to its circumference is equidistant.

Area of a circle = πr²

Where :

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Determine whether 5, 238 is divisible by 2, 3, 4, 5, 6, 9, or 10.
Gelneren [198K]

Answer:

2, 3, 6

Step-by-step explanation:

Simply try each value using long division.

2:

Since 5,238 ends in an even number, that automatically means it is divisible by 2.

5238/2=2619

Now for 3:

5238/3=1746 no remainder or decimal, so 3 also works

4:

You can either do long division again with 4, or you can see if 5238 divided by 2 (5238/2) is also divisible by 2. Since 2619 doesn't end in an even number, 4 is a no go.

Long division 5238/4=1309.5 decimal here, so 4 isn't an answer

5:

This is also very easy, simply check if the number ends in 0 or 5. Since 5,238 does not, 5 doesn't work either.

6:

You can do the same thing as with 4, except this time trying to find if 5238 divided by 3 (5238/3) is divisible by 2. Since 1746 ends in an even number, 6 also works.

Long division: 5238/6=873

9:

You can do the same thing as with 6, except this time trying to find if 5238 divided by 3 (5238/3) is divisible by 3.

1746/3=548 with a remainder of 2, which means 9 doesn't work

Long division: 5238/9=548.66 repeating

10:

Finally, 10 is another easy one. Simply check if the number ends in 0. 5,238 does not, so 10 doesn't work.

5 0
2 years ago
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