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harkovskaia [24]
3 years ago
5

Butanone draw both enolates formed when the ketone is treated with base. include charges. draw the oxyanion species; do not draw

carbanion resonance forms.

Chemistry
1 answer:
hjlf3 years ago
8 0
This is an example of deprotonation of Asymmetric Ketones. In this case two products are possible.

Thermodynamic Product:
                                        It gives highly substituted enolate, has greater transition energy to cross and has lower product energy.

Kinetic Product:
                         It gives less substituted enolate, the proton is accessible and easily removed and has less transition energy, and higher product energy compared to thermodynamic product.

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galben [10]

The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
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PV = nRT

1.5 × 12 = n × 0.0821 × 280

18 = n × 22.988

Divide both side by 22.988

n = 18 / 22.988

n = 0.783 mole

Next, we shall determine the mole of NaCl needed for the reaction.

F₂ + 2NaCl —> Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.

Finally, we shall determine the mass of 1.566 moles of NaCl.

  • Mole = 1.566 moles
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

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