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harkovskaia [24]
3 years ago
5

Butanone draw both enolates formed when the ketone is treated with base. include charges. draw the oxyanion species; do not draw

carbanion resonance forms.

Chemistry
1 answer:
hjlf3 years ago
8 0
This is an example of deprotonation of Asymmetric Ketones. In this case two products are possible.

Thermodynamic Product:
                                        It gives highly substituted enolate, has greater transition energy to cross and has lower product energy.

Kinetic Product:
                         It gives less substituted enolate, the proton is accessible and easily removed and has less transition energy, and higher product energy compared to thermodynamic product.

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Answer:

Gas, has no shape but does take up volume

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What pressure is exerted by 932.3 g of CH4 in a 0.560 L steel container at 136.2 K?
Roman55 [17]
Molar mass CH4 = 16.0 g/mol

* number of moles:

932.3 / 16 => 58.26875 moles

T = 136.2 K

V = 0.560 L

P = ?

R = 0.082

Use the clapeyron equation:

P x V = n x R x T

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5 0
3 years ago
A sample of methane gas, CH4, occupies 3.25 L at temperature of 19.0 o C. If the pressure is held constant, what will be the tem
Artemon [7]

Answer:

625.46 °C

Explanation:

We'll begin by converting 19 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 19 °C

T(K) = 19 °C + 273

T(K) = 292 K

Next, we shall determine the Final temperature. This can be obtained as follow:

Initial volume (V₁) = 3.25 L

Initial temperature (T₁) = 292 K

Final volume (V₂) = 10 L

Final temperature (T₂) =?

V₁/T₁ = V₂/T₂

3.25 / 292 = 10 / T₂

Cross multiply

3.25 × T₂ = 292 × 10

3.25 × T₂ = 2920

Divide both side by 3.25

T₂ = 2920 / 3.25

T₂ = 898.46 K

Finally, we shall convert 898.46 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 898.46 K

T(°C) = 898.46 – 273

T(°C) = 625.46 °C

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4 0
3 years ago
Which beaker has the least thermal energy?
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Breaker A

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