1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NARA [144]
3 years ago
12

John rode 3150 m at an average speed of 350 m/min.If he had ridden at average of 375 m/min instead. How much sooner would it hav

e taken? (In seconds)​
Chemistry
1 answer:
Svet_ta [14]3 years ago
7 0

Explanation:

Given that:

Distance traveled = 3150m

Average speed = 350m/min

Suggested speed = 375m/min

Unknown:

Time = ?

Solution:

Speed is the rate of change of distance with time.

  it is mathematically expressed as;

     speed = \frac{distance }{time}

Initial time using speed 350m/min can be calculated by making time the subject of the formula;

     time taken = \frac{distance }{speed}

    time taken at speed of speed of 350m/min = \frac{3150}{350} = 9min

   to seconds = 9 x 60 = 540 seconds

  time taken at speed of 375m/min = \frac{3150}{375} = 8.4min

   to seconds = 8.4 x 60 = 504 seconds.

It could have taken 504 seconds sooner saving 36 seconds.

learn more:

Speed brainly.com/question/10177389

#learnwithBrainly

You might be interested in
PLEASE HELP URGENT!!!! ( photo included)
Aliun [14]
Water, lower, and I'm not too sure for the third one... sorry.
5 0
3 years ago
if you have a bf and he has a crush on another girl and that girl likes him to. is he cheating on you
olya-2409 [2.1K]

Answer:

techinically no. unless he does something with her. or kisses her. but i would break up with him if he doesn't like you/not interested. i am so sorry this is happening to you

Explanation:

3 0
2 years ago
Read 2 more answers
What is name of each shape​
dimulka [17.4K]

Answer:

I am so sorry I do not know this

Explanation:

4 0
2 years ago
Which best illustrates the way in which radiation? Giving brainy.
Ilya [14]

Answer:

I dont really understand your question. but maybe this might help.

https://quizlet.com/283377931/radiation-flash-cards/

Explanation:

4 0
2 years ago
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
Other questions:
  • Please answer number 76,77 and 78.
    15·1 answer
  • Calcium oxide (CaO) reacts with tetraphosphorus decoxide (P4O10) to form calcium phosphate (Ca3(P4O10)2) according to this equat
    10·1 answer
  • What is the electron geometry of PF3?
    14·1 answer
  • How can the difference in the brightness of spectral lines be explained
    12·1 answer
  • Do you just add the two masses?
    13·1 answer
  • 1. Which liquid sample is a pure substance?
    11·1 answer
  • You need to produce a buffer solution that has a pH of 4.97. You already have a solution that contains 10. mmol (millimoles) of
    9·1 answer
  • How does changing the initial mass of the cooper affects how much heat energy it has?
    12·1 answer
  • How many atoms of carbon are in 6.00g of carbon?(Mm of carbon is<br> 12g/mol)
    13·1 answer
  • Write correctly a balanced equation for the following "word" equation: Red lead → lead monoxide + oxygen​
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!