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asambeis [7]
3 years ago
5

If a chemist has 17.8 moles of N2H4O3, what is the mass of the sample? show work plz

Chemistry
1 answer:
harkovskaia [24]3 years ago
4 0

(\frac{17.8mole}{1} )( \frac{66grams}{1mole} ) \:  \:  \:  \:  17.8 \times 66 = 1.17 \times  {10}^{3} grams
the way that you get 66 is by adding he atomic mass unit of each atom in the formula. so N2 is 14 + 14 H4 is 1 * 4 and 03 is 16 * 3
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3 0
3 years ago
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6 0
3 years ago
Read 2 more answers
PLEASE ANSWER THIS QUESTION FAST :(
kramer
Mol sulfuric acid = 19 g * (1 mol) / (98.1 g) = 0.19367 mol
mol H2O = 0.19367 mol H2SO4 * (2 H2O) / (1 H2SO4)
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6 0
3 years ago
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