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asambeis [7]
3 years ago
5

If a chemist has 17.8 moles of N2H4O3, what is the mass of the sample? show work plz

Chemistry
1 answer:
harkovskaia [24]3 years ago
4 0

(\frac{17.8mole}{1} )( \frac{66grams}{1mole} ) \:  \:  \:  \:  17.8 \times 66 = 1.17 \times  {10}^{3} grams
the way that you get 66 is by adding he atomic mass unit of each atom in the formula. so N2 is 14 + 14 H4 is 1 * 4 and 03 is 16 * 3
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what is an empirical formulaWhat is the percent composition by mass of nitrogen in (NH4)2CO3 (gram-formula mass = 96.0 g/mol)?
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Answer:

Percentage composition = 14.583%

Explanation:

In chemistry, the emprical formular of a compound is the simplest formular a compound can have. It shows the simplest ratio in which the elements are combined in the compound.

Percentage composition by mass of Nitrogen

Nitrogen = 14g/mol

In one mole of the compound;

Mass of Nitrogen = 1 mol * 14g/mol = 14g

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Percentage composition of Nitrogen = (Mass of Nitrogen /  Mass of compound) * 100

percentage composition = 14/96   * 100

Percentage composition = 0.14583 * 100

Percentage composition = 14.583%

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