2 years ago

If a chemist has 17.8 moles of N2H4O3, what is the mass of the sample? show work plz

1 answer:

4 0

$(\frac{17.8mole}{1} )( \frac{66grams}{1mole} ) \: \: \: \: 17.8 \times 66 = 1.17 \times {10}^{3} grams$
the way that you get 66 is by adding he atomic mass unit of each atom in the formula. so N2 is 14 + 14 H4 is 1 * 4 and 03 is 16 * 3

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