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slamgirl [31]
2 years ago
8

Electrons must be able to flow through a material in order for the material to conduct

Chemistry
1 answer:
djverab [1.8K]2 years ago
7 0

The molecular structure of the solids has lower ability to conduct electricity due to tight holding by nucleus.

<h3>Why molecular solids are poor conductors?</h3>

Molecular solids are also poor conductors of electricity because their valence electrons are tightly held by the nuclear charges present in the nucleus while on the other hand, Metals are good electrical conductors in the solid form due to the presence of free electrons that helps in the conduction of electricity.

Learn more about electricity here: brainly.com/question/25144822

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PLEASE HELP ASAP ESSAY WORTH 15 POINTS! ONLY GENIUS!
Sliva [168]

Answer:

According to the law of conservation of mass, the mass of reactants will be equal to the mass of the products.

Explanation:

5 0
3 years ago
How much heat is required to raise the temperature of 225 grams of ice from -26.8 °C to steam at 133 °C ?
lara [203]
<h3>Answer:</h3>

150000 J

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J)
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C or K)

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>m</em> = 225 g

[Given] <em>c</em> = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] <em>q</em>

<u>Step 2: Solve for </u><em><u>q</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                          q = (225 g)(4.184 J/g °C)(159.8 °C)
  2. Multiply:                                                                                                           q = (941.4 J/°C)(159.8 °C)
  3. Multiply:                                                                                                           q = 150436 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

5 0
3 years ago
How many moles are in 20 grams of sodium
tatyana61 [14]
0.869952156982 to be precise
7 0
3 years ago
A brine solution of salt flows at a constant rate of 4L/min into a large tank that initially held 100L of pure water. The solutio
ella [17]

Answer:

To reach 01.kg/L concentration of salt in the tank will take around 18.9 min

Explanation:

Attached

8 0
3 years ago
Read 2 more answers
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S 2 ( g ) + C ( s ) − ⇀ ↽ − CS 2 ( g ) K c
bezimeni [28]

Answer:

974.6 grams of CS2 can be prepared.

Explanation:

<u>Step 1:</u> Data given

Kc = 9.40 at 900 K

Moles of S2 = 14.2 mol

volume = 6.30 L

Molar mass of CS2 = 76.14 g/mol

<u>Step 2:</u> The balanced equation:

S2(g)+C(s) ↔ CS2(g)

<u>Step 3:</u> Calculate initial concentrations

Concentration of S2 = moles S2  / volume

Concentration of S2 = 14.2 moles / 6.30 L

Concentration of S2 = 2.25 M (This is the initial concentration)

The initial concentration of C and CS2 is 0M

Since the mole ratio is 1:1:1

There will react X

The concentration of S2 at the equilibrium is: (2.25 -X)M

The concentration of C and CS2 at the equilibrium is X M

<u>Step 4:</u> Calculate concentrations

Since C is not a gas but solid, it doesn't matter for the Kc

Kc = 9.40 = (products)/(reactants) = [CS2(g)]/[S2(g)]

9.40 = X/(2.25-X)

X = 2.034 = [CS2]

[S2] = 2.25 - 2.034 = 0.216

<u>Step 5</u>: Calculate moles of CS2

Moles CS2 = molarity CS2 * volume

Moles CS2 = 2.034 M * 6.30 L

Moles CS2 = 12.8 moles

<u>Step 6:</u> Calculate mass of CS2

Mass CS2 = moles CS2 * molar mass CS2

Mass CS2 = 12.8 moles * 76.14 g/mol

Mass CS2 = 974.6 grams

974.6 grams of CS2 can be prepared.

6 0
3 years ago
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