Please please please help me
1 answer:
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Answer:
Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:
Plug -2 for one of the slopes.
Divide by -2 to find the slope of our line.
Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:
Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:
Simplify and distribute:
Subtract 4 from both sides:
The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
<h2>Option B is the correct answer.</h2>
Step-by-step explanation:
We need to find average value of in [2,4]
Area of in [2,4] is given by
Area of in [2,4] = 1463.18
Difference = 4 - 2 = 2
Average value = Area of in [2,4] ÷ Difference
Average value = 1463.18 ÷ 2
Average value = 731.59
Option B is the correct answer.