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3 years ago

Fruit for thought part 2

Mathematics

1 answer:

s2008m [1.1K]3 years ago

8 0

Answer:

Banana = 6, the rest is in the picture

Step-by-step explanation:

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The measure of EC bisects

stepladder [879]

Answer:

The value of x = 20

Step-by-step explanation:

Given:

∠BOC = 3x - 15

∠COD = 2x + 5

Find:

The value of x

Computation:

⇔ ∠BOC + ∠COD = 90

⇔ 3x - 15 + 2x + 5 = 90

⇔ 5x - 10 = 900

⇔ 5x = 90 + 10

⇔ 5x = 100

⇔ x = 100 / 5

⇔ x = 20

The value of x = 20

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3 years ago

A ______ is a graph of data based on quartiles showing a rectangle with lines extending from both its ends.

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A box and whisker plot

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3 years ago

Sole for y k = p/2(y+w) y =

mojhsa [17]

Answer:

Answer: y = (2k -pw)/p

Step-by-step explanation:

$k = \frac{p}{2} (y + w)$

multiply 2 on both sides:

$k \times 2 = 2 \times \frac{p}{2} (y + w) \\ \\ 2k = p(y + w)$

open the bracket:

$2k = py + pw$

subtract pw from both sides:

$2k - pw = (py + pw) - pw \\ 2k - pw = py$

divide p on both sides:

$\frac{2k - pw}{p} = \frac{py}{p} \\ \\ y = \frac{2k - pw}{p}$

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3 years ago

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Which expression represents the volume, in cubic units, of

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Answer:It's A. I just took the test on e2020

Step-by-step explanation:

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3 years ago

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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$