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3 years ago

The widths of two similar rectangles are 25 ft. and 20 ft. What is the ratio of the perimeters?

Mathematics

1 answer:

dlinn [17]3 years ago

5 0

All linear dimensions of similar figures are in the same ratio.
The perimeters are also in the ratio of 5 to 4.

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The ratio of boys to girls in history class is 4to5 how many girls are in class if there are 12 boys in the class

DENIUS [597]

The answer is 15 girls

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3 years ago

Read 2 more answers

Find the number of pairs (a,b) of integers such that<br> a+2/a+5=b/3

Viktor [21]

Answer:

Step-by-step explanation:

The expression can be rearranged to ...

b = 3 -9/(a+5)

In order for b to be an integer, (a+5) must be an integer divisor of 9. There are exactly 6 of those: ±1, ±3, ±9.

The attached table shows the values (a, b) = (x₁, f(x₁)).

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3 years ago

Find the volumes of the solids generated by revolving the triangle with vertices (2, 2), (2, 6), and (5, 6) about a) the x-a

Vesna [10]

About the $x$ -axis (washer method):

$\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}$

About the $y$ -axis (shell method):

$\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}$

About $x=7$ (shell method):

$\displaystyle2\pi\int_2^5(7-x)\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5(35-12x+x^2)\,\mathrm dx=\boxed{48\pi}$

About $y=2$ (washer method):

$\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}$

7 0

3 years ago

PLEASE HELP ASAP!!!!!!!!!

Butoxors [25]

Answer:

it’s the last one

8 0

2 years ago

Find two numbers whose difference is 102 and whose product is a minimum. Step 1 If two numbers have a difference of 102, and one

NISA [10]

Answer:

The two numbers would be -51 and 51

Step-by-step explanation:

To find these, first set the equation for the first number as x. You can then set the second number as x + 102. Now, find their product.

x(x + 102) = x^2 + 102x

Now, to find the minimum, find the value of x in the vertex of this equation.

-b/2a = -102/2(1) = -102/2 = -51

So we know -51 is the first number. Now we find the second using the prewritten equation.

x + 102 = -51 + 102 = 51

4 0

3 years ago