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Eduardwww [97]
3 years ago
5

The length of a rectangle is 9 cm more then half the width. Find the length of the perimeter is 60cm

Mathematics
1 answer:
stira [4]3 years ago
7 0

length = 1/2 w+9

perimeter= 60 =2(l+w)  

substitute in for length

60 = 2(1/2 w +9 +w)  

60 = 2 (3/2 w +9)

distribute

60 = 3w + 18

subtract 18 from each side

42 = 3w

divide by 3 on each side

14 = w

length = 1/2 w + 9

length = 1/2 (14) +9

              7 + 9

16cm

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A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
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2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
\overline {OB}:10 = 1:2
\overline{OB} = \frac{1}{2}(10) = 5

Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
\overline {AO}:10 = \sqrt{3}:2
\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

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Question 1 Answer:

Aunt 1 and Grandma 1 would fill gift bags.

Mom and Aunt 2 would make centerpieces.

You and Grandma 2 would blow up balloons.

Since you are pairing up to complete the tasks, these pairs each have the shortest times in their respective categories and therefore are the most logical pairing to complete tasks.

Question 2 Answer:

We use algebra and our previous pairings to determine the length of each task.

<u>Gifts Bags --> 6/7 hours</u>

x = time together

\frac{1}{x} = rate of completion

Aunt 1 = \frac{1}{1.5} Grandma 1 = \frac{1}{2}

\frac{2}{3} +\frac{1}{2} = \frac{1}{x}

\frac{7}{6} = \frac{1}{x}

x = \frac{6}{7}

<u>Centerpieces --> 7/4 hours</u>

x = time together    \frac{1}{x} = rate of completion

Mom = \frac{1}{3.5} Aunt 2 = \frac{1}{3.5}

\frac{2}{7} + \frac{2}{7}  = \frac{1}{x}

\frac{4}{7} = \frac{1}{x}

x = \frac{7}{4}

<u>Balloons --> 15/16 hours</u>

x = time together    \frac{1}{x} = rate of completion

You = \frac{1}{1.5} Grandma 2 = \frac{1}{2.5}

\frac{2}{3} + \frac{2}{5}  = \frac{1}{x}

\frac{16}{15} = \frac{1}{x}

x = \frac{15}{16}

Shortest amount of time to complete all tasks is:

\frac{6}{7} + \frac{7}{4} + \frac{15}{16} = \frac{397}{112}  ≈ 3.54 hours

Converting hours to hours and minutes --> 3 hours 32 minutes

Therefore they must arrive by 5:28pm to complete the tasks in time to leave at 9:00pm.

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