Given:
Point D is the centroid of Triangle ABC and DE = 9.
To find:
The measures of CD and CE.
Solution:
We know that, centroid is the intersection of medians and it divides each median in 2:1.
In triangle ABC, CE is a meaning and centroid D divided CE in 2:1. So,
Let the measures of CD and DE are 2x and x respectively.
DE = 9 (Given)
![x=9](https://tex.z-dn.net/?f=x%3D9)
Now,
![CD=2x](https://tex.z-dn.net/?f=CD%3D2x)
![CD=2(9)](https://tex.z-dn.net/?f=CD%3D2%289%29)
![CD=18](https://tex.z-dn.net/?f=CD%3D18)
And,
![CE=CD+DE](https://tex.z-dn.net/?f=CE%3DCD%2BDE)
![CE=18+9](https://tex.z-dn.net/?f=CE%3D18%2B9)
![CE=27](https://tex.z-dn.net/?f=CE%3D27)
Therefore, the measure of CD is 18 units and the measure of CE is 27 units.
Answer:
700=700
Step-by-step explanation:
Answer:
The general term for the sequence can be given by the following formula:
![a_n=2\,n+9](https://tex.z-dn.net/?f=a_n%3D2%5C%2Cn%2B9)
Step-by-step explanation:
If the sequence you typed starts with first term 11 and continues with terms 13, 15, 17, 19, We understand that the sequence is formed by adding 2 units to the previous term. So we are in the case of an arithmetic sequence with constant difference (d) = 2, and with first term 11.
Therefore, the nth term of this arithmetic sequence can be expressed by using the general form for an arithmetic sequence as:
![a_n=a_1\,+\,(n-1)\,d\\a_n=11\,+\,(n-1)\,2\\a_n=11+2\,n-2\\a_n=2\,n+9](https://tex.z-dn.net/?f=a_n%3Da_1%5C%2C%2B%5C%2C%28n-1%29%5C%2Cd%5C%5Ca_n%3D11%5C%2C%2B%5C%2C%28n-1%29%5C%2C2%5C%5Ca_n%3D11%2B2%5C%2Cn-2%5C%5Ca_n%3D2%5C%2Cn%2B9)